freebsd-dev/usr.bin/calendar/paskha.c

67 lines
2.1 KiB
C
Raw Normal View History

/*-
* Copyright (C) 1993-1996 by Andrey A. Chernov, Moscow, Russia.
* All rights reserved.
*
* Redistribution and use in source and binary forms, with or without
* modification, are permitted provided that the following conditions
* are met:
* 1. Redistributions of source code must retain the above copyright
* notice, this list of conditions and the following disclaimer.
* 2. Redistributions in binary form must reproduce the above copyright
* notice, this list of conditions and the following disclaimer in the
* documentation and/or other materials provided with the distribution.
*
* THIS SOFTWARE IS PROVIDED BY THE AUTHOR ``AS IS'' AND
* ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
* IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
* ARE DISCLAIMED. IN NO EVENT SHALL THE REGENTS OR CONTRIBUTORS BE LIABLE
* FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
* DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
* OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
* HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
* LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
* OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
* SUCH DAMAGE.
*/
#include <sys/cdefs.h>
__FBSDID("$FreeBSD$");
1996-05-11 20:44:21 +00:00
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include "calendar.h"
#define PASKHA "paskha"
#define PASKHALEN (sizeof(PASKHA) - 1)
/* return difference in days between Julian and Gregorian calendars */
int
j2g(int year)
{
return (year < 1500) ?
0 :
10 + (year/100 - 16) - ((year/100 - 16) / 4);
}
/* return year day for Orthodox Easter using Gauss formula */
/* (new style result) */
int
paskha(int R) /*year*/
{
int a, b, c, d, e;
static int x = 15;
static int y = 6;
int *cumday;
a = R % 19;
b = R % 4;
c = R % 7;
d = (19 * a + x) % 30;
e = (2 * b + 4 * c + 6 * d + y) % 7;
cumday = cumdaytab[isleap(R)];
return (((cumday[3] + 1) + 22) + (d + e) + j2g(R));
}