1994-09-29 23:04:24 +00:00
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/*
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1993-12-21 18:36:48 +00:00
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* makeIPFP - make fast DES IP and FP tables
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*
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* This is an older version which generated tables half the size of
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* the current version, but which took about double the CPU time to
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* compute permutations from these tables. Since the CPU spent on the
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* permutations is small compared to the CPU spent in the cipher code,
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* I may go back to the smaller tables to save the space some day.
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*/
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#include <stdio.h>
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#include <sys/types.h>
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#include "ntp_stdlib.h"
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#define STREQ(a, b) (*(a) == *(b) && strcmp((a), (b)) == 0)
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1994-09-29 23:04:24 +00:00
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u_long IPL[8][16];
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u_long FPL[8][16];
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1993-12-21 18:36:48 +00:00
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char *progname;
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int debug;
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1994-09-29 23:04:24 +00:00
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static void perm P((u_char *, u_char *, u_long *, u_long *));
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1993-12-21 18:36:48 +00:00
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static void doit P((void));
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/*
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* main - parse arguments and handle options
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*/
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void
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main(argc, argv)
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int argc;
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char *argv[];
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{
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int c;
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int errflg = 0;
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1994-02-03 22:09:07 +00:00
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extern int ntp_optind;
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extern char *ntp_optarg;
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1993-12-21 18:36:48 +00:00
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progname = argv[0];
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1994-02-03 22:09:07 +00:00
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while ((c = ntp_getopt(argc, argv, "d")) != EOF)
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1993-12-21 18:36:48 +00:00
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switch (c) {
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case 'd':
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++debug;
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break;
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default:
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errflg++;
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break;
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}
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if (errflg) {
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(void) fprintf(stderr, "usage: %s [-d]\n", progname);
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exit(2);
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}
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doit();
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exit(0);
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}
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/*
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* Initial permutation table
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*/
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u_char IP[64] = {
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58, 50, 42, 34, 26, 18, 10, 2,
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60, 52, 44, 36, 28, 20, 12, 4,
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62, 54, 46, 38, 30, 22, 14, 6,
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64, 56, 48, 40, 32, 24, 16, 8,
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57, 49, 41, 33, 25, 17, 9, 1,
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59, 51, 43, 35, 27, 19, 11, 3,
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61, 53, 45, 37, 29, 21, 13, 5,
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63, 55, 47, 39, 31, 23, 15, 7
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};
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/*
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* Inverse initial permutation table
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*/
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u_char FP[64] = {
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40, 8, 48, 16, 56, 24, 64, 32,
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39, 7, 47, 15, 55, 23, 63, 31,
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38, 6, 46, 14, 54, 22, 62, 30,
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37, 5, 45, 13, 53, 21, 61, 29,
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36, 4, 44, 12, 52, 20, 60, 28,
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35, 3, 43, 11, 51, 19, 59, 27,
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34, 2, 42, 10, 50, 18, 58, 26,
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33, 1, 41, 9, 49, 17, 57, 25
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};
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/*
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* Bit order after the operation
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*
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* ((left & 0x55555555) << 1) | (right & 0x55555555)
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*/
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u_char IPLbits[32] = {
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2, 34, 4, 36, 6, 38, 8, 40,
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10, 42, 12, 44, 14, 46, 16, 48,
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18, 50, 20, 52, 22, 54, 24, 56,
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26, 58, 28, 60, 30, 62, 32, 64
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};
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/*
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* Bit order after the operation
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*
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* (left & 0xaaaaaaaa) | ((right & 0xaaaaaaaa) >> 1)
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*/
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u_char IPRbits[32] = {
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1, 33, 3, 35, 5, 37, 7, 39,
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9, 41, 11, 43, 13, 45, 15, 47,
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17, 49, 19, 51, 21, 53, 23, 55,
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25, 57, 27, 59, 29, 61, 31, 63
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};
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/*
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* Bit order after the operation
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*
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* ((left & 0x0f0f0f0f) << 4) | (right & 0x0f0f0f0f)
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*/
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u_char FPLbits[32] = {
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5, 6, 7, 8, 37, 38, 39, 40,
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13, 14, 15, 16, 45, 46, 47, 48,
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21, 22, 23, 24, 53, 54, 55, 56,
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29, 30, 31, 32, 61, 62, 63, 64
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};
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/*
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* Bit order after the operation
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*
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* (left & 0xf0f0f0f0) | ((right & 0xf0f0f0f0) >> 4)
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*/
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u_char FPRbits[32] = {
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1, 2, 3, 4, 33, 34, 35, 36,
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9, 10, 11, 12, 41, 42, 43, 44,
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17, 18, 19, 20, 49, 50, 51, 52,
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25, 26, 27, 28, 57, 58, 59, 60
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};
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/*
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* perm - do a permutation with the given table
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*/
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static void
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perm(databits, permtab, leftp, rightp)
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u_char *databits;
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u_char *permtab;
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1994-09-29 23:04:24 +00:00
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u_long *leftp;
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u_long *rightp;
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1993-12-21 18:36:48 +00:00
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{
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1994-09-29 23:04:24 +00:00
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register u_long left;
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register u_long right;
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1993-12-21 18:36:48 +00:00
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register u_char *PT;
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register u_char *bits;
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register int i;
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left = right = 0;
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PT = permtab;
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bits = databits;
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for (i = 0; i < 32; i++) {
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left <<= 1;
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if (bits[PT[i]-1])
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left |= 1;
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}
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for (i = 32; i < 64; i++) {
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right <<= 1;
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if (bits[PT[i]-1])
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right |= 1;
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}
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*leftp = left;
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*rightp = right;
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}
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/*
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* doit - make up the tables
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*/
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static void
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doit()
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{
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u_char bits[64];
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1994-09-29 23:04:24 +00:00
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u_long left;
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u_long right;
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1993-12-21 18:36:48 +00:00
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int tabno;
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int i;
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int ind0, ind1, ind2, ind3;
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int quadbits;
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1994-02-03 22:09:07 +00:00
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memset((char *)bits, 0, sizeof bits);
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1993-12-21 18:36:48 +00:00
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/*
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* Do the rounds for the IPL table. We save the results of
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* this as well as printing them. Note that this is the
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* left-half table.
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*/
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1994-09-29 23:04:24 +00:00
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printf("static u_long IP[8][16] = {");
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1993-12-21 18:36:48 +00:00
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for (tabno = 0; tabno < 8; tabno++) {
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i = tabno * 4;
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ind3 = IPLbits[i] - 1;
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ind2 = IPLbits[i+1] - 1;
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ind1 = IPLbits[i+2] - 1;
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ind0 = IPLbits[i+3] - 1;
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for (quadbits = 0; quadbits < 16; quadbits++) {
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if (quadbits & (1 << 3))
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bits[ind3] = 1;
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if (quadbits & (1 << 2))
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bits[ind2] = 1;
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if (quadbits & (1 << 1))
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bits[ind1] = 1;
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if (quadbits & 1)
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bits[ind0] = 1;
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perm(bits, IP, &left, &right);
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bits[ind3] = 0;
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bits[ind2] = 0;
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bits[ind1] = 0;
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bits[ind0] = 0;
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if (right != 0) {
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fprintf(stderr,
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"IPL tabno %d quad %d right not zero\n",
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tabno, quadbits);
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exit(1);
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}
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IPL[tabno][quadbits] = left;
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if (quadbits == 15 && tabno == 7) {
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printf(" 0x%08x", left);
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} else if (quadbits & 0x3) {
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printf(" 0x%08x,", left);
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} else {
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printf("\n\t0x%08x,", left);
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}
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}
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if (tabno == 7)
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printf("\n};\n");
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printf("\n");
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}
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/*
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* Compute the right half of the same table. I noticed this table
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* was the same as the previous one, just by luck, so we don't
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* actually have to do this. Do it anyway just for a check.
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*/
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for (tabno = 0; tabno < 8; tabno++) {
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i = tabno * 4;
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ind3 = IPRbits[i] - 1;
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ind2 = IPRbits[i+1] - 1;
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ind1 = IPRbits[i+2] - 1;
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ind0 = IPRbits[i+3] - 1;
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for (quadbits = 0; quadbits < 16; quadbits++) {
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if (quadbits & (1 << 3))
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bits[ind3] = 1;
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if (quadbits & (1 << 2))
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bits[ind2] = 1;
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if (quadbits & (1 << 1))
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bits[ind1] = 1;
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if (quadbits & 1)
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bits[ind0] = 1;
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perm(bits, IP, &left, &right);
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bits[ind3] = 0;
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bits[ind2] = 0;
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bits[ind1] = 0;
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bits[ind0] = 0;
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if (left != 0) {
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fprintf(stderr,
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"IPR tabno %d quad %d left not zero\n",
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tabno, quadbits);
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exit(1);
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}
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if (right != IPL[tabno][quadbits]) {
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fprintf(stderr,
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"IPR tabno %d quad %d: 0x%08x not same as 0x%08x\n",
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tabno, quadbits, right,IPL[tabno][quadbits]);
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exit(1);
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}
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}
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}
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/*
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* Next are the FP tables
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*/
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1994-09-29 23:04:24 +00:00
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printf("static u_long FP[8][16] = {");
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1993-12-21 18:36:48 +00:00
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for (tabno = 0; tabno < 8; tabno++) {
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i = tabno * 4;
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ind3 = FPLbits[i] - 1;
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ind2 = FPLbits[i+1] - 1;
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ind1 = FPLbits[i+2] - 1;
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ind0 = FPLbits[i+3] - 1;
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for (quadbits = 0; quadbits < 16; quadbits++) {
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if (quadbits & (1 << 3))
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bits[ind3] = 1;
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if (quadbits & (1 << 2))
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bits[ind2] = 1;
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if (quadbits & (1 << 1))
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bits[ind1] = 1;
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if (quadbits & 1)
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bits[ind0] = 1;
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perm(bits, FP, &left, &right);
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bits[ind3] = 0;
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bits[ind2] = 0;
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bits[ind1] = 0;
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bits[ind0] = 0;
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if (right != 0) {
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fprintf(stderr,
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"FPL tabno %d quad %d right not zero\n",
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tabno, quadbits);
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exit(1);
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}
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FPL[tabno][quadbits] = left;
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if (quadbits == 15 && tabno == 7) {
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printf(" 0x%08x", left);
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} else if (quadbits & 0x3) {
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printf(" 0x%08x,", left);
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} else {
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printf("\n\t0x%08x,", left);
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}
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}
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if (tabno == 7)
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printf("\n};");
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printf("\n");
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}
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/*
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* Right half of same set of tables. This was symmetric too.
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* Amazing!
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*/
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for (tabno = 0; tabno < 8; tabno++) {
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i = tabno * 4;
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ind3 = FPRbits[i] - 1;
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ind2 = FPRbits[i+1] - 1;
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ind1 = FPRbits[i+2] - 1;
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ind0 = FPRbits[i+3] - 1;
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for (quadbits = 0; quadbits < 16; quadbits++) {
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if (quadbits & (1 << 3))
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bits[ind3] = 1;
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if (quadbits & (1 << 2))
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bits[ind2] = 1;
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if (quadbits & (1 << 1))
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bits[ind1] = 1;
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if (quadbits & 1)
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bits[ind0] = 1;
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perm(bits, FP, &left, &right);
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bits[ind3] = 0;
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bits[ind2] = 0;
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bits[ind1] = 0;
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bits[ind0] = 0;
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if (left != 0) {
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fprintf(stderr,
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"FPR tabno %d quad %d left not zero\n",
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tabno, quadbits);
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exit(1);
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}
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if (right != FPL[tabno][quadbits]) {
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fprintf(stderr,
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"FPR tabno %d quad %d: 0x%08x not same as 0x%08x\n",
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tabno, quadbits, right,FPL[tabno][quadbits]);
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exit(1);
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}
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}
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}
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}
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