Fixing ABD struct allocation for FreeBSD
In the event we are allocating a gang ABD in FreeBSD we are passing 0 to abd_alloc_struct(); however, this led to an allocation of ABD scatter with 0 chunks. This left the gang ABD allocation 24 bytes smaller than it should have been. Reviewed-by: Matt Macy <mmacy@FreeBSD.org> Reviewed-by: Brian Behlendorf <behlendorf1@llnl.gov> Co-authored-by: Matt Macy <mmacy@FreeBSD.org> Signed-off-by: Brian Atkinson <batkinson@lanl.gov> Closes #10431
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@ -198,8 +198,15 @@ abd_t *
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abd_alloc_struct(size_t size)
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{
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size_t chunkcnt = abd_chunkcnt_for_bytes(size);
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size_t abd_size = offsetof(abd_t,
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abd_u.abd_scatter.abd_chunks[chunkcnt]);
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/*
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* In the event we are allocating a gang ABD, the size passed in
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* will be 0. We must make sure to set abd_size to the size of an
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* ABD struct as opposed to an ABD scatter with 0 chunks. The gang
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* ABD struct allocation accounts for an additional 24 bytes over
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* a scatter ABD with 0 chunks.
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*/
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size_t abd_size = MAX(sizeof (abd_t),
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offsetof(abd_t, abd_u.abd_scatter.abd_chunks[chunkcnt]));
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abd_t *abd = kmem_alloc(abd_size, KM_PUSHPAGE);
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ASSERT3P(abd, !=, NULL);
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list_link_init(&abd->abd_gang_link);
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@ -212,8 +219,10 @@ abd_alloc_struct(size_t size)
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void
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abd_free_struct(abd_t *abd)
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{
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size_t chunkcnt = abd_is_linear(abd) ? 0 : abd_scatter_chunkcnt(abd);
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int size = offsetof(abd_t, abd_u.abd_scatter.abd_chunks[chunkcnt]);
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size_t chunkcnt = abd_is_linear(abd) || abd_is_gang(abd) ? 0 :
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abd_scatter_chunkcnt(abd);
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int size = MAX(sizeof (abd_t),
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offsetof(abd_t, abd_u.abd_scatter.abd_chunks[chunkcnt]));
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mutex_destroy(&abd->abd_mtx);
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ASSERT(!list_link_active(&abd->abd_gang_link));
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kmem_free(abd, size);
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