Fix the broken "avoid unaligned data" fix. The problem is that the builtin

gcc memcpy "knows" about types that are supposed to be actually already
aligned and triggers alignment errors doing the memcpy itself.
"Fix" this by changing it to a bcopy().  In this case, we had:
  struct timeval *tp;
  struct timeval tv1;
  memcpy(&tv1,tp,sizeof(tv1));
.. and since gcc *knows* that a pointer to a timeval is longword aligned
and that tv1 is longword aligned, then it can use an inline that assumes
alignment.  The following works too:
  cp = (char *)tp;
  memcpy(&tv1,cp,sizeof(tv1));
Simply casting (char *)tp  for the memcpy doesn't work. :-(
This affected different 64 bit platforms in different ways and depends
a lot on gcc as well.  I've seen this on alpha and ia64 at least, although
alpha isn't doing it right now.
This commit is contained in:
Peter Wemm 2002-08-10 03:00:55 +00:00
parent fd35706acb
commit 11bad678c6
Notes: svn2git 2020-12-20 02:59:44 +00:00
svn path=/head/; revision=101623

View File

@ -841,8 +841,8 @@ pr_pack(buf, cc, from, tv)
#else
tp = (struct timeval *)icp->icmp_data;
#endif
/* Avoid unaligned data: */
memcpy(&tv1,tp,sizeof(tv1));
/* Avoid unaligned data (cannot use memcpy) */
bcopy(tp, &tv1, sizeof(tv1));
tvsub(tv, &tv1);
triptime = ((double)tv->tv_sec) * 1000.0 +
((double)tv->tv_usec) / 1000.0;