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For the P function, the newline must be considered a part of the pattern

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space, so when printing it, don't let the pattern space and the output run
into eachother by omitting the \n when printing.
This commit is contained in:
Juli Mallett 2002-04-21 01:27:05 +00:00
parent dd281fa589
commit 151740b470
Notes: svn2git 2020-12-20 02:59:44 +00:00 
svn path=/head/; revision=95169
2 changed files with 12 additions and 1 deletions
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8
tools/regression/usr.bin/sed/regress.P.out Normal file
View File

@ -0,0 +1,8 @@
input
input
data
data
for validation
for validation
of sed(1)
of sed(1)

5
tools/regression/usr.bin/sed/regress.sh
View File

@ -9,12 +9,15 @@ cd $TESTDIR
STATUS=0
for test in G psl; do
for test in G P psl; do
echo "Running test $test"
case "$test" in
G)
sed G < regress.in | diff -u regress.$test.out -
;;
P)
sed P < regress.in | diff -u regress.$test.out -
;;
psl)
sed '$!g; P; D' < regress.in | diff -u regress.$test.out -
;;