malloc_aligned() may not leave enough space for pointer to allocated memory,

saving the pointer will overwrite bytes belongs to another memory block
unexpectly, to fix the problem, use (allocated address + sizeof(void *)) as
initial value, and slip to next aligned address, so maximum extra bytes is
sizeof(void *) + align - 1.

Tested by: Andre Albsmeier < mail at ma17 dot ata dot myota dot orgndre >
This commit is contained in:
David Xu 2014-02-21 03:36:16 +00:00
parent 182d7debb9
commit 209782e06f
Notes: svn2git 2020-12-20 02:59:44 +00:00
svn path=/head/; revision=262277

View File

@ -72,14 +72,14 @@ void *
malloc_aligned(size_t size, size_t align)
{
void *mem, *res;
uintptr_t x;
size_t asize, r;
r = round(sizeof(void *), align);
asize = round(size, align) + r;
mem = xmalloc(asize);
x = (uintptr_t)mem;
res = (void *)round(x, align);
if (align & (sizeof(void *) -1)) {
rtld_fdputstr(STDERR_FILENO, "Invalid alignment\n");
_exit(1);
}
mem = xmalloc(size + sizeof(void *) + align - 1);
res = (void *)round((uintptr_t)mem + sizeof(void *), align);
*(void **)((uintptr_t)res - sizeof(void *)) = mem;
return (res);
}