Fix calculating l0index in _pmap_alloc_l3 on arm64
When moving from the l1 index to l0 index we need to use the l1 shift value not the l0 shift value. With 4k pages they are identical, however with 16k pages we only have 2 l0 entries so the shift value is incorrect. Reviewed by: alc, markj Sponsored by: The FreeBSD Foundation Differential Revision: https://reviews.freebsd.org/D34517
This commit is contained in:
parent
0977ebb071
commit
5e2f304cb4
@ -1945,7 +1945,7 @@ _pmap_alloc_l3(pmap_t pmap, vm_pindex_t ptepindex, struct rwlock **lockp)
|
||||
pd_entry_t tl0;
|
||||
|
||||
l1index = ptepindex - NUL2E;
|
||||
l0index = l1index >> L0_ENTRIES_SHIFT;
|
||||
l0index = l1index >> Ln_ENTRIES_SHIFT;
|
||||
|
||||
l0 = &pmap->pm_l0[l0index];
|
||||
tl0 = pmap_load(l0);
|
||||
@ -1973,7 +1973,7 @@ _pmap_alloc_l3(pmap_t pmap, vm_pindex_t ptepindex, struct rwlock **lockp)
|
||||
pd_entry_t tl0, tl1;
|
||||
|
||||
l1index = ptepindex >> Ln_ENTRIES_SHIFT;
|
||||
l0index = l1index >> L0_ENTRIES_SHIFT;
|
||||
l0index = l1index >> Ln_ENTRIES_SHIFT;
|
||||
|
||||
l0 = &pmap->pm_l0[l0index];
|
||||
tl0 = pmap_load(l0);
|
||||
|
Loading…
Reference in New Issue
Block a user