51369649b0
Mainly focus on files that use BSD 3-Clause license. The Software Package Data Exchange (SPDX) group provides a specification to make it easier for automated tools to detect and summarize well known opensource licenses. We are gradually adopting the specification, noting that the tags are considered only advisory and do not, in any way, superceed or replace the license texts. Special thanks to Wind River for providing access to "The Duke of Highlander" tool: an older (2014) run over FreeBSD tree was useful as a starting point.
147 lines
4.2 KiB
C
147 lines
4.2 KiB
C
/*-
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* SPDX-License-Identifier: BSD-3-Clause
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*
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* Copyright (c) 1987, 1993
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* The Regents of the University of California. All rights reserved.
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*
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* Redistribution and use in source and binary forms, with or without
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* modification, are permitted provided that the following conditions
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* are met:
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* 1. Redistributions of source code must retain the above copyright
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* notice, this list of conditions and the following disclaimer.
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* 2. Redistributions in binary form must reproduce the above copyright
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* notice, this list of conditions and the following disclaimer in the
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* documentation and/or other materials provided with the distribution.
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* 3. Neither the name of the University nor the names of its contributors
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* may be used to endorse or promote products derived from this software
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* without specific prior written permission.
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*
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* THIS SOFTWARE IS PROVIDED BY THE REGENTS AND CONTRIBUTORS ``AS IS'' AND
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* ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
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* IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
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* ARE DISCLAIMED. IN NO EVENT SHALL THE REGENTS OR CONTRIBUTORS BE LIABLE
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* FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
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* DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
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* OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
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* HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
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* LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
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* OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
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* SUCH DAMAGE.
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*/
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#include <sys/cdefs.h>
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__FBSDID("$FreeBSD$");
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#include <sys/libkern.h>
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#include <machine/endian.h>
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typedef const void *cvp;
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typedef const unsigned char *ustring;
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typedef unsigned long ul;
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typedef const unsigned long *culp;
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/*
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* bcmp -- vax cmpc3 instruction
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*/
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int
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bcmp(const void *b1, const void *b2, size_t length)
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{
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#if BYTE_ORDER == LITTLE_ENDIAN
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/*
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* The following code is endian specific. Changing it from
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* little-endian to big-endian is fairly trivial, but making
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* it do both is more difficult.
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*
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* Note that this code will reference the entire longword which
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* includes the final byte to compare. I don't believe this is
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* a problem since AFAIK, objects are not protected at smaller
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* than longword boundaries.
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*/
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int shl, shr, len = length;
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ustring p1 = b1, p2 = b2;
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ul va, vb;
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if (len == 0)
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return (0);
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/*
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* align p1 to a longword boundary
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*/
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while ((long)p1 & (sizeof(long) - 1)) {
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if (*p1++ != *p2++)
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return (1);
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if (--len <= 0)
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return (0);
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}
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/*
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* align p2 to longword boundary and calculate the shift required to
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* align p1 and p2
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*/
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shr = (long)p2 & (sizeof(long) - 1);
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if (shr != 0) {
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p2 -= shr; /* p2 now longword aligned */
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shr <<= 3; /* offset in bits */
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shl = (sizeof(long) << 3) - shr;
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va = *(culp)p2;
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p2 += sizeof(long);
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while ((len -= sizeof(long)) >= 0) {
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vb = *(culp)p2;
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p2 += sizeof(long);
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if (*(culp)p1 != (va >> shr | vb << shl))
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return (1);
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p1 += sizeof(long);
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va = vb;
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}
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/*
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* At this point, len is between -sizeof(long) and -1,
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* representing 0 .. sizeof(long)-1 bytes remaining.
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*/
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if (!(len += sizeof(long)))
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return (0);
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len <<= 3; /* remaining length in bits */
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/*
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* The following is similar to the `if' condition
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* inside the above while loop. The ?: is necessary
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* to avoid accessing the longword after the longword
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* containing the last byte to be compared.
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*/
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return ((((va >> shr | ((shl < len) ? *(culp)p2 << shl : 0)) ^
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*(culp)p1) & ((1L << len) - 1)) != 0);
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} else {
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/* p1 and p2 have common alignment so no shifting needed */
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while ((len -= sizeof(long)) >= 0) {
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if (*(culp)p1 != *(culp)p2)
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return (1);
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p1 += sizeof(long);
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p2 += sizeof(long);
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}
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/*
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* At this point, len is between -sizeof(long) and -1,
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* representing 0 .. sizeof(long)-1 bytes remaining.
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*/
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if (!(len += sizeof(long)))
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return (0);
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return (((*(culp)p1 ^ *(culp)p2)
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& ((1L << (len << 3)) - 1)) != 0);
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}
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#else
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const char *p1, *p2;
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if (length == 0)
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return(0);
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p1 = b1;
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p2 = b2;
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do
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if (*p1++ != *p2++)
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break;
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while (--length);
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return(length);
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#endif
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}
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