SHA* routines so that callers of libcrypt are not exposed to the internal implementation.
186 lines
4.4 KiB
C
186 lines
4.4 KiB
C
/*
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* ----------------------------------------------------------------------------
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* "THE BEER-WARE LICENSE" (Revision 42):
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* <phk@login.dknet.dk> wrote this file. As long as you retain this notice you
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* can do whatever you want with this stuff. If we meet some day, and you think
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* this stuff is worth it, you can buy me a beer in return. Poul-Henning Kamp
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* ----------------------------------------------------------------------------
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*
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* $FreeBSD$
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*
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*/
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#if defined(LIBC_SCCS) && !defined(lint)
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static const char rcsid[] = \
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"$FreeBSD$";
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#endif /* LIBC_SCCS and not lint */
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#include <unistd.h>
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#include <stdio.h>
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#include <string.h>
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#include <md5.h>
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#include <err.h>
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#include "crypt.h"
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#ifdef __PIC__
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#include <dlfcn.h>
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#define MD5Init(ctx) dl_MD5Init(ctx)
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#define MD5Update(ctx, data, len) dl_MD5Update(ctx, data, len)
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#define MD5Final(dgst, ctx) dl_MD5Final(dgst, ctx)
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static void (*dl_MD5Init)(MD5_CTX *);
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static void (*dl_MD5Update)(MD5_CTX *, const unsigned char *, unsigned int);
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static void (*dl_MD5Final)(unsigned char digest[16], MD5_CTX *);
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#endif
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/*
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* UNIX password
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*/
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char *
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crypt_md5(pw, salt)
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const char *pw;
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const char *salt;
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{
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static char *magic = "$1$"; /*
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* This string is magic for
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* this algorithm. Having
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* it this way, we can get
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* get better later on
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*/
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static char passwd[120], *p;
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static const char *sp,*ep;
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unsigned char final[MD5_SIZE];
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int sl,pl,i;
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MD5_CTX ctx,ctx1;
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unsigned long l;
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#ifdef __PIC__
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void *libmd;
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#endif
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/* Refine the Salt first */
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sp = salt;
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/* If it starts with the magic string, then skip that */
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if(!strncmp(sp,magic,strlen(magic)))
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sp += strlen(magic);
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/* It stops at the first '$', max 8 chars */
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for(ep=sp;*ep && *ep != '$' && ep < (sp+8);ep++)
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continue;
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/* get the length of the true salt */
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sl = ep - sp;
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#ifdef __PIC__
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libmd = dlopen("libmd.so", RTLD_NOW);
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if (libmd == NULL)
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return NULL;
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dl_MD5Init = dlsym(libmd, "MD5Init");
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if (dl_MD5Init == NULL) {
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warnx("libcrypt-md5: looking for MD5Init: %s\n", dlerror());
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dlclose(libmd);
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return NULL;
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}
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dl_MD5Update = dlsym(libmd, "MD5Update");
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if (dl_MD5Update == NULL) {
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warnx("libcrypt-md5: looking for MD5Update: %s\n", dlerror());
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dlclose(libmd);
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return NULL;
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}
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dl_MD5Final = dlsym(libmd, "MD5Final");
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if (dl_MD5Final == NULL) {
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warnx("libcrypt-md5: looking for MD5Final: %s\n", dlerror());
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dlclose(libmd);
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return NULL;
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}
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#endif
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MD5Init(&ctx);
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/* The password first, since that is what is most unknown */
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MD5Update(&ctx,pw,strlen(pw));
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/* Then our magic string */
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MD5Update(&ctx,magic,strlen(magic));
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/* Then the raw salt */
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MD5Update(&ctx,sp,sl);
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/* Then just as many characters of the MD5(pw,salt,pw) */
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MD5Init(&ctx1);
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MD5Update(&ctx1,pw,strlen(pw));
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MD5Update(&ctx1,sp,sl);
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MD5Update(&ctx1,pw,strlen(pw));
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MD5Final(final,&ctx1);
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for(pl = strlen(pw); pl > 0; pl -= MD5_SIZE)
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MD5Update(&ctx,final,pl>MD5_SIZE ? MD5_SIZE : pl);
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/* Don't leave anything around in vm they could use. */
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memset(final,0,sizeof final);
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/* Then something really weird... */
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for (i = strlen(pw); i ; i >>= 1)
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if(i&1)
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MD5Update(&ctx, final, 1);
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else
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MD5Update(&ctx, pw, 1);
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/* Now make the output string */
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strcpy(passwd,magic);
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strncat(passwd,sp,sl);
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strcat(passwd,"$");
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MD5Final(final,&ctx);
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/*
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* and now, just to make sure things don't run too fast
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* On a 60 Mhz Pentium this takes 34 msec, so you would
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* need 30 seconds to build a 1000 entry dictionary...
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*/
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for(i=0;i<1000;i++) {
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MD5Init(&ctx1);
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if(i & 1)
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MD5Update(&ctx1,pw,strlen(pw));
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else
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MD5Update(&ctx1,final,MD5_SIZE);
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if(i % 3)
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MD5Update(&ctx1,sp,sl);
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if(i % 7)
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MD5Update(&ctx1,pw,strlen(pw));
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if(i & 1)
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MD5Update(&ctx1,final,MD5_SIZE);
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else
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MD5Update(&ctx1,pw,strlen(pw));
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MD5Final(final,&ctx1);
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}
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#ifdef __PIC__
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dlclose(libmd);
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#endif
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p = passwd + strlen(passwd);
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l = (final[ 0]<<16) | (final[ 6]<<8) | final[12];
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_crypt_to64(p,l,4); p += 4;
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l = (final[ 1]<<16) | (final[ 7]<<8) | final[13];
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_crypt_to64(p,l,4); p += 4;
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l = (final[ 2]<<16) | (final[ 8]<<8) | final[14];
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_crypt_to64(p,l,4); p += 4;
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l = (final[ 3]<<16) | (final[ 9]<<8) | final[15];
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_crypt_to64(p,l,4); p += 4;
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l = (final[ 4]<<16) | (final[10]<<8) | final[ 5];
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_crypt_to64(p,l,4); p += 4;
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l = final[11] ;
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_crypt_to64(p,l,2); p += 2;
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*p = '\0';
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/* Don't leave anything around in vm they could use. */
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memset(final,0,sizeof final);
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return passwd;
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}
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