8ef6f9f2d2
Pre-r206145 sh changes nested arithmetic substitution to parentheses, which is not always correct, as exercised by this test.
18 lines
299 B
Plaintext
18 lines
299 B
Plaintext
# $FreeBSD$
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failures=0
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check() {
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if [ "$2" != "$3" ]; then
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failures=$((failures+1))
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echo "For $1, expected $3 actual $2"
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fi
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}
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unset a
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check '$((1+${a:-$((7+2))}))' "$((1+${a:-$((7+2))}))" 10
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check '$((1+${a:=$((2+2))}))' "$((1+${a:=$((2+2))}))" 5
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check '$a' "$a" 4
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exit $((failures != 0))
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