109 lines
3.5 KiB
C
109 lines
3.5 KiB
C
/*-
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* Copyright 1998 Juniper Networks, Inc.
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* All rights reserved.
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*
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* Redistribution and use in source and binary forms, with or without
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* modification, are permitted provided that the following conditions
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* are met:
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* 1. Redistributions of source code must retain the above copyright
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* notice, this list of conditions and the following disclaimer.
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* 2. Redistributions in binary form must reproduce the above copyright
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* notice, this list of conditions and the following disclaimer in the
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* documentation and/or other materials provided with the distribution.
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*
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* THIS SOFTWARE IS PROVIDED BY THE AUTHOR AND CONTRIBUTORS ``AS IS'' AND
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* ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
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* IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
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* ARE DISCLAIMED. IN NO EVENT SHALL THE AUTHOR OR CONTRIBUTORS BE LIABLE
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* FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
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* DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
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* OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
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* HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
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* LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
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* OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
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* SUCH DAMAGE.
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*
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* $FreeBSD$
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*/
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#include <syslog.h> /* XXX */
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#include <stdio.h>
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#include <string.h>
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#include <skey.h>
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#define PAM_SM_AUTH
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#include <security/pam_modules.h>
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#include "pam_mod_misc.h"
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PAM_EXTERN int
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pam_sm_authenticate(pam_handle_t *pamh, int flags, int argc,
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const char **argv)
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{
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int retval;
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const char *user;
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const char *response;
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struct skey skey;
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char challenge[128];
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char prompt[128];
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char resp_buf[128];
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int options;
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int i;
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int e;
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options = 0;
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for (i = 0; i < argc; i++)
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pam_std_option(&options, argv[i]);
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/*
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* It doesn't make sense to use a password that has already been
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* typed in, since we haven't presented the challenge to the user
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* yet.
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*/
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options &= ~(PAM_OPT_USE_FIRST_PASS | PAM_OPT_TRY_FIRST_PASS);
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if ((retval = pam_get_user(pamh, &user, NULL)) != PAM_SUCCESS)
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return retval;
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if (skeyinfo(&skey, user, challenge) != 0)
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return PAM_AUTH_ERR;
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snprintf(prompt, sizeof prompt, "%s\nPassword: ", challenge);
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if ((retval = pam_get_pass(pamh, &response, prompt, options)) !=
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PAM_SUCCESS)
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return retval;
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if (response[0] == '\0' && !(options & PAM_OPT_ECHO_PASS)) {
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options |= PAM_OPT_ECHO_PASS;
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snprintf(prompt, sizeof prompt,
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"%s\nPassword [echo on]: ", challenge);
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if ((retval = pam_get_pass(pamh, &response, prompt,
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options)) != PAM_SUCCESS)
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return retval;
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}
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/*
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* Skeyinfo closed the database file, so we have to call skeylookup
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* to open it again.
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*/
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if ((e = skeylookup(&skey, user)) != 0) {
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if (e == -1) {
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syslog(LOG_ERR, "Error opening S/Key database");
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return PAM_SERVICE_ERR;
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} else
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return PAM_AUTH_ERR;
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}
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/* We have to copy the response, because skeyverify mucks with it. */
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snprintf(resp_buf, sizeof resp_buf, "%s", response);
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/*
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* Skeyverify is supposed to return -1 only if an error occurs.
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* But it returns -1 even if the response string isn't in the form
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* it expects. Thus we can't log an error and can only check for
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* success or lack thereof.
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*/
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return skeyverify(&skey, resp_buf) == 0 ? PAM_SUCCESS : PAM_AUTH_ERR;
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}
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PAM_EXTERN int
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pam_sm_setcred(pam_handle_t *pamh, int flags, int argc, const char **argv)
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{
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return PAM_SUCCESS;
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}
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PAM_MODULE_ENTRY("pam_skey");
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