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- Fix schedgraph output with KSE threads. Call thread_switchout() after

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calling CTR() so we don't confuse a new kse thread with a real preemption.
This commit is contained in:
Jeff Roberson 2007-01-03 02:38:41 +00:00
parent 8313a4905c
commit b1c00b13d6
1 changed files with 8 additions and 4 deletions
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12
sys/kern/kern_synch.c
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@ -407,10 +407,6 @@ mi_switch(int flags, struct thread *newtd)
PCPU_SET(switchticks, ticks);
CTR4(KTR_PROC, "mi_switch: old thread %p (kse %p, pid %ld, %s)",
(void *)td, td->td_sched, (long)p->p_pid, p->p_comm);
#ifdef KSE
if ((flags & SW_VOL) && (td->td_proc->p_flag & P_SA))
newtd = thread_switchout(td, flags, newtd);
#endif
#if (KTR_COMPILE & KTR_SCHED) != 0
if (td == PCPU_GET(idlethread))
CTR3(KTR_SCHED, "mi_switch: %p(%s) prio %d idle",
@ -425,6 +421,14 @@ mi_switch(int flags, struct thread *newtd)
"mi_switch: %p(%s) prio %d inhibit %d wmesg %s lock %s",
td, td->td_proc->p_comm, td->td_priority,
td->td_inhibitors, td->td_wmesg, td->td_lockname);
#endif
/*
* We call thread_switchout after the KTR_SCHED prints above so kse
* selecting a new thread to run does not show up as a preemption.
*/
#ifdef KSE
if ((flags & SW_VOL) && (td->td_proc->p_flag & P_SA))
newtd = thread_switchout(td, flags, newtd);
#endif
sched_switch(td, newtd, flags);
CTR3(KTR_SCHED, "mi_switch: running %p(%s) prio %d",