5ebfa8de69
The main argument is that it is impossible to determine if %n evaluated or not when snprintf return 0, because it can happens for both n == 0 and n == 1. Although EOF here is good indication of the end of process, if n is decreased in the loop... Since it is already supposed in many places that EOF *is* negative, f.e. from Single Unix specs for snprintf "return ... a negative value if an output error was encountered" this not makes situation worse. |
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amd64 | ||
compat-43 | ||
db | ||
gen | ||
gmon | ||
i386 | ||
locale | ||
net | ||
nls | ||
quad | ||
regex | ||
rpc | ||
stdio | ||
stdlib | ||
stdtime | ||
string | ||
sys | ||
xdr | ||
yp | ||
Makefile | ||
Makefile.inc |