398 lines
11 KiB
C
398 lines
11 KiB
C
/* $NetBSD: str.c,v 1.86 2021/06/21 16:59:18 rillig Exp $ */
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/*
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* Copyright (c) 1988, 1989, 1990, 1993
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* The Regents of the University of California. All rights reserved.
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*
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* This code is derived from software contributed to Berkeley by
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* Adam de Boor.
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*
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* Redistribution and use in source and binary forms, with or without
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* modification, are permitted provided that the following conditions
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* are met:
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* 1. Redistributions of source code must retain the above copyright
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* notice, this list of conditions and the following disclaimer.
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* 2. Redistributions in binary form must reproduce the above copyright
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* notice, this list of conditions and the following disclaimer in the
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* documentation and/or other materials provided with the distribution.
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* 3. Neither the name of the University nor the names of its contributors
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* may be used to endorse or promote products derived from this software
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* without specific prior written permission.
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*
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* THIS SOFTWARE IS PROVIDED BY THE REGENTS AND CONTRIBUTORS ``AS IS'' AND
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* ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
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* IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
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* ARE DISCLAIMED. IN NO EVENT SHALL THE REGENTS OR CONTRIBUTORS BE LIABLE
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* FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
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* DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
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* OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
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* HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
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* LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
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* OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
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* SUCH DAMAGE.
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*/
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/*
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* Copyright (c) 1989 by Berkeley Softworks
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* All rights reserved.
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*
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* This code is derived from software contributed to Berkeley by
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* Adam de Boor.
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*
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* Redistribution and use in source and binary forms, with or without
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* modification, are permitted provided that the following conditions
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* are met:
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* 1. Redistributions of source code must retain the above copyright
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* notice, this list of conditions and the following disclaimer.
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* 2. Redistributions in binary form must reproduce the above copyright
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* notice, this list of conditions and the following disclaimer in the
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* documentation and/or other materials provided with the distribution.
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* 3. All advertising materials mentioning features or use of this software
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* must display the following acknowledgement:
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* This product includes software developed by the University of
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* California, Berkeley and its contributors.
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* 4. Neither the name of the University nor the names of its contributors
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* may be used to endorse or promote products derived from this software
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* without specific prior written permission.
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*
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* THIS SOFTWARE IS PROVIDED BY THE REGENTS AND CONTRIBUTORS ``AS IS'' AND
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* ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
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* IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
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* ARE DISCLAIMED. IN NO EVENT SHALL THE REGENTS OR CONTRIBUTORS BE LIABLE
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* FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
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* DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
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* OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
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* HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
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* LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
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* OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
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* SUCH DAMAGE.
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*/
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#include "make.h"
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/* "@(#)str.c 5.8 (Berkeley) 6/1/90" */
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MAKE_RCSID("$NetBSD: str.c,v 1.86 2021/06/21 16:59:18 rillig Exp $");
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/* Return the concatenation of s1 and s2, freshly allocated. */
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char *
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str_concat2(const char *s1, const char *s2)
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{
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size_t len1 = strlen(s1);
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size_t len2 = strlen(s2);
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char *result = bmake_malloc(len1 + len2 + 1);
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memcpy(result, s1, len1);
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memcpy(result + len1, s2, len2 + 1);
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return result;
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}
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/* Return the concatenation of s1, s2 and s3, freshly allocated. */
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char *
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str_concat3(const char *s1, const char *s2, const char *s3)
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{
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size_t len1 = strlen(s1);
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size_t len2 = strlen(s2);
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size_t len3 = strlen(s3);
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char *result = bmake_malloc(len1 + len2 + len3 + 1);
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memcpy(result, s1, len1);
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memcpy(result + len1, s2, len2);
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memcpy(result + len1 + len2, s3, len3 + 1);
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return result;
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}
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/*
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* Fracture a string into an array of words (as delineated by tabs or spaces)
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* taking quotation marks into account.
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*
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* If expand is true, quotes are removed and escape sequences such as \r, \t,
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* etc... are expanded. In this case, return NULL on parse errors.
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*
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* Returns the fractured words, which must be freed later using Words_Free,
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* unless the returned Words.words was NULL.
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*/
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SubstringWords
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Substring_Words(const char *str, bool expand)
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{
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size_t str_len;
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char *words_buf;
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size_t words_cap;
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Substring *words;
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size_t words_len;
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char inquote;
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char *word_start;
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char *word_end;
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const char *str_p;
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/* XXX: why only hspace, not whitespace? */
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cpp_skip_hspace(&str); /* skip leading space chars. */
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/* words_buf holds the words, separated by '\0'. */
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str_len = strlen(str);
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words_buf = bmake_malloc(str_len + 1);
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words_cap = str_len / 5 > 50 ? str_len / 5 : 50;
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words = bmake_malloc((words_cap + 1) * sizeof(words[0]));
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/*
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* copy the string; at the same time, parse backslashes,
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* quotes and build the word list.
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*/
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words_len = 0;
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inquote = '\0';
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word_start = words_buf;
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word_end = words_buf;
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for (str_p = str;; str_p++) {
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char ch = *str_p;
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switch (ch) {
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case '"':
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case '\'':
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if (inquote != '\0') {
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if (inquote == ch)
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inquote = '\0';
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else
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break;
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} else {
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inquote = ch;
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/* Don't miss "" or '' */
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if (word_start == NULL && str_p[1] == inquote) {
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if (!expand) {
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word_start = word_end;
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*word_end++ = ch;
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} else
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word_start = word_end + 1;
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str_p++;
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inquote = '\0';
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break;
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}
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}
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if (!expand) {
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if (word_start == NULL)
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word_start = word_end;
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*word_end++ = ch;
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}
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continue;
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case ' ':
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case '\t':
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case '\n':
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if (inquote != '\0')
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break;
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if (word_start == NULL)
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continue;
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/* FALLTHROUGH */
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case '\0':
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/*
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* end of a token -- make sure there's enough words
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* space and save off a pointer.
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*/
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if (word_start == NULL)
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goto done;
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*word_end++ = '\0';
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if (words_len == words_cap) {
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words_cap *= 2;
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words = bmake_realloc(words,
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(words_cap + 1) * sizeof(words[0]));
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}
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words[words_len++] =
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Substring_Init(word_start, word_end - 1);
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word_start = NULL;
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if (ch == '\n' || ch == '\0') {
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if (expand && inquote != '\0') {
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SubstringWords res;
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free(words);
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free(words_buf);
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res.words = NULL;
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res.len = 0;
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res.freeIt = NULL;
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return res;
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}
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goto done;
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}
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continue;
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case '\\':
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if (!expand) {
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if (word_start == NULL)
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word_start = word_end;
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*word_end++ = '\\';
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/* catch '\' at end of line */
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if (str_p[1] == '\0')
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continue;
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ch = *++str_p;
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break;
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}
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switch (ch = *++str_p) {
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case '\0':
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case '\n':
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/* hmmm; fix it up as best we can */
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ch = '\\';
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str_p--;
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break;
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case 'b':
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ch = '\b';
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break;
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case 'f':
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ch = '\f';
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break;
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case 'n':
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ch = '\n';
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break;
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case 'r':
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ch = '\r';
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break;
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case 't':
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ch = '\t';
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break;
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}
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break;
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}
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if (word_start == NULL)
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word_start = word_end;
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*word_end++ = ch;
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}
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done:
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words[words_len] = Substring_Init(NULL, NULL); /* useful for argv */
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{
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SubstringWords result;
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result.words = words;
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result.len = words_len;
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result.freeIt = words_buf;
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return result;
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}
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}
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Words
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Str_Words(const char *str, bool expand)
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{
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SubstringWords swords;
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Words words;
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size_t i;
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swords = Substring_Words(str, expand);
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if (swords.words == NULL) {
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words.words = NULL;
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words.len = 0;
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words.freeIt = NULL;
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return words;
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}
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words.words = bmake_malloc((swords.len + 1) * sizeof(words.words[0]));
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words.len = swords.len;
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words.freeIt = swords.freeIt;
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for (i = 0; i < swords.len + 1; i++)
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words.words[i] = UNCONST(swords.words[i].start);
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free(swords.words);
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return words;
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}
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/*
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* Str_Match -- Test if a string matches a pattern like "*.[ch]".
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* The following special characters are known *?\[] (as in fnmatch(3)).
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*
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* XXX: this function does not detect or report malformed patterns.
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*/
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bool
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Str_Match(const char *str, const char *pat)
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{
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for (;;) {
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/*
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* See if we're at the end of both the pattern and the
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* string. If so, we succeeded. If we're at the end of the
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* pattern but not at the end of the string, we failed.
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*/
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if (*pat == '\0')
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return *str == '\0';
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if (*str == '\0' && *pat != '*')
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return false;
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/*
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* A '*' in the pattern matches any substring. We handle this
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* by calling ourselves for each suffix of the string.
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*/
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if (*pat == '*') {
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pat++;
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while (*pat == '*')
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pat++;
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if (*pat == '\0')
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return true;
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while (*str != '\0') {
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if (Str_Match(str, pat))
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return true;
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str++;
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}
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return false;
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}
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/* A '?' in the pattern matches any single character. */
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if (*pat == '?')
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goto thisCharOK;
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/*
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* A '[' in the pattern matches a character from a list.
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* The '[' is followed by the list of acceptable characters,
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* or by ranges (two characters separated by '-'). In these
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* character lists, the backslash is an ordinary character.
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*/
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if (*pat == '[') {
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bool neg = pat[1] == '^';
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pat += neg ? 2 : 1;
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for (;;) {
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if (*pat == ']' || *pat == '\0') {
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if (neg)
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break;
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return false;
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}
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/*
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* XXX: This naive comparison makes the
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* control flow of the pattern parser
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* dependent on the actual value of the
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* string. This is unpredictable. It may be
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* though that the code only looks wrong but
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* actually all code paths result in the same
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* behavior. This needs further tests.
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*/
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if (*pat == *str)
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break;
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if (pat[1] == '-') {
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if (pat[2] == '\0')
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return neg;
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if (*pat <= *str && pat[2] >= *str)
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break;
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if (*pat >= *str && pat[2] <= *str)
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break;
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pat += 2;
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}
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pat++;
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}
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if (neg && *pat != ']' && *pat != '\0')
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return false;
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while (*pat != ']' && *pat != '\0')
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pat++;
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if (*pat == '\0')
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pat--;
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goto thisCharOK;
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}
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/*
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* A backslash in the pattern matches the character following
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* it exactly.
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*/
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if (*pat == '\\') {
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pat++;
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if (*pat == '\0')
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return false;
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}
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if (*pat != *str)
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return false;
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thisCharOK:
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pat++;
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str++;
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}
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}
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