When bitpos can't be implemented with an inline ffs* instruction,
change the binary search so that it does not depend on a single bit only being set in the bitmask. Use bitpos more generally, and avoid some clearing of bits to accommodate its current behavior. Approved by: kib (mentor) Differential Revision: https://reviews.freebsd.org/D20237
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@ -192,30 +192,40 @@ bitrange(int n, int count)
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/*
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* Use binary search, or a faster method, to find the 1 bit in a u_daddr_t.
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* Assumes that the argument has only one bit set.
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* Find the first bit set in a u_daddr_t.
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*/
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static inline int
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generic_bitpos(u_daddr_t mask)
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{
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int hi, lo, mid;
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lo = 0;
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hi = BLIST_BMAP_RADIX;
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while (lo + 1 < hi) {
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mid = (lo + hi) >> 1;
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if (mask & bitrange(0, mid))
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hi = mid;
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else
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lo = mid;
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}
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return (lo);
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}
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static inline int
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bitpos(u_daddr_t mask)
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{
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int hi, lo, mid;
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switch (sizeof(mask)) {
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#ifdef HAVE_INLINE_FFSLL
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case sizeof(long long):
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return (ffsll(mask) - 1);
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#endif
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#ifdef HAVE_INLINE_FFS
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case sizeof(int):
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return (ffs(mask) - 1);
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#endif
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default:
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lo = 0;
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hi = BLIST_BMAP_RADIX;
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while (lo + 1 < hi) {
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mid = (lo + hi) >> 1;
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if ((mask >> mid) != 0)
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lo = mid;
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else
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hi = mid;
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}
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return (lo);
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return (generic_bitpos(mask));
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}
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}
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@ -532,7 +542,8 @@ blist_stats(blist_t bl, struct sbuf *s)
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struct gap_stats gstats;
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struct gap_stats *stats = &gstats;
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daddr_t i, nodes, radix;
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u_daddr_t bit, diff, mask;
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u_daddr_t diff, mask;
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int digit;
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init_gap_stats(stats);
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nodes = 0;
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@ -570,9 +581,9 @@ blist_stats(blist_t bl, struct sbuf *s)
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if (gap_stats_counting(stats))
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diff ^= 1;
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while (diff != 0) {
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bit = diff & -diff;
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update_gap_stats(stats, i + bitpos(bit));
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diff ^= bit;
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digit = bitpos(diff);
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update_gap_stats(stats, i + digit);
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diff ^= bitrange(digit, 1);
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}
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}
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nodes += radix_to_skip(radix);
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@ -776,7 +787,7 @@ static daddr_t
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blst_meta_alloc(blmeta_t *scan, daddr_t cursor, daddr_t count, u_daddr_t radix)
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{
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daddr_t blk, i, r, skip;
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u_daddr_t bit, mask;
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u_daddr_t mask;
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bool scan_from_start;
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int digit;
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@ -808,8 +819,7 @@ blst_meta_alloc(blmeta_t *scan, daddr_t cursor, daddr_t count, u_daddr_t radix)
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* Examine the nonempty subtree associated with each bit set in mask.
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*/
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do {
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bit = mask & -mask;
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digit = bitpos(bit);
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digit = bitpos(mask);
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i = 1 + digit * skip;
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if (count <= scan[i].bm_bighint) {
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/*
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@ -819,12 +829,12 @@ blst_meta_alloc(blmeta_t *scan, daddr_t cursor, daddr_t count, u_daddr_t radix)
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count, radix);
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if (r != SWAPBLK_NONE) {
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if (scan[i].bm_bitmap == 0)
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scan->bm_bitmap ^= bit;
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scan->bm_bitmap ^= bitrange(digit, 1);
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return (r);
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}
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}
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cursor = blk;
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} while ((mask ^= bit) != 0);
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} while ((mask ^= bitrange(digit, 1)) != 0);
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/*
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* We couldn't allocate count in this subtree. If the whole tree was
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@ -1019,7 +1029,7 @@ static void
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blst_radix_print(blmeta_t *scan, daddr_t blk, daddr_t radix, int tab)
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{
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daddr_t skip;
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u_daddr_t bit, mask;
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u_daddr_t mask;
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int digit;
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if (radix == BLIST_BMAP_RADIX) {
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@ -1051,11 +1061,10 @@ blst_radix_print(blmeta_t *scan, daddr_t blk, daddr_t radix, int tab)
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mask = scan->bm_bitmap;
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/* Examine the nonempty subtree associated with each bit set in mask */
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do {
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bit = mask & -mask;
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digit = bitpos(bit);
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digit = bitpos(mask);
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blst_radix_print(&scan[1 + digit * skip], blk + digit * radix,
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radix, tab);
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} while ((mask ^= bit) != 0);
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} while ((mask ^= bitrange(digit, 1)) != 0);
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tab -= 4;
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printf(
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