tvtohz will print out an error message if a negative value is given

to it, avoid this problem by detecting timeout earlier.

Reported by: pho
This commit is contained in:
davidxu 2012-08-11 00:06:56 +00:00
parent 5b837de0b3
commit 43c8a8efc2

View File

@ -587,11 +587,10 @@ abs_timeout_init2(struct abs_timeout *timo, const struct _umtx_time *umtxtime)
&umtxtime->_timeout);
}
static int
static void
abs_timeout_update(struct abs_timeout *timo)
{
kern_clock_gettime(curthread, timo->clockid, &timo->cur);
return (timespeccmp(&timo->cur, &timo->end, >=));
}
static int
@ -601,6 +600,8 @@ abs_timeout_gethz(struct abs_timeout *timo)
tts = timo->end;
timespecsub(&tts, &timo->cur);
if (tts.tv_sec < 0 || (tts.tv_sec == 0 && tts.tv_nsec == 0))
return (-1);
return (tstohz(&tts));
}
@ -613,22 +614,25 @@ umtxq_sleep(struct umtx_q *uq, const char *wmesg, struct abs_timeout *timo)
{
struct umtxq_chain *uc;
int error;
int pulse;
uc = umtxq_getchain(&uq->uq_key);
UMTXQ_LOCKED_ASSERT(uc);
for (;;) {
if (!(uq->uq_flags & UQF_UMTXQ))
return (0);
error = msleep(uq, &uc->uc_lock, PCATCH, wmesg,
timo == NULL ? 0 : abs_timeout_gethz(timo));
if (error != EWOULDBLOCK)
break;
umtxq_unlock(&uq->uq_key);
if (abs_timeout_update(timo)) {
error = ETIMEDOUT;
if (timo != NULL) {
pulse = abs_timeout_gethz(timo);
if (pulse < 0)
return (ETIMEDOUT);
} else
pulse = 0;
error = msleep(uq, &uc->uc_lock, PCATCH|PDROP, wmesg, pulse);
if (error != EWOULDBLOCK) {
umtxq_lock(&uq->uq_key);
break;
}
abs_timeout_update(timo);
umtxq_lock(&uq->uq_key);
}
return (error);