sed(1): partial fix for the case of the regex delimited with '['.
We don't generally support the weird case of regular expresions delimited by an opening square bracket ('[') but POSIX says that inside bracket expressions, escaping is not possible and both '[' and '\' represent themselves. PR: 230198 (exp-run) Obtained from: OpenBSD
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@ -393,11 +393,11 @@ compile_delimited(char *p, char *d, int is_tr)
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if ((d = compile_ccl(&p, d)) == NULL)
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errx(1, "%lu: %s: unbalanced brackets ([])", linenum, fname);
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continue;
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} else if (*p == '\\' && p[1] == c) {
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p++;
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} else if (*p == '\\' && p[1] == '[') {
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*d++ = *p++;
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} else if (*p == '\\' && p[1] == c)
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p++;
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else if (*p == '\\' && p[1] == 'n') {
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} else if (*p == '\\' && p[1] == 'n') {
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*d++ = '\n';
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p += 2;
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continue;
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