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Replace (Qo \ Qc) with (Qo (space) Qc)

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When using col(1) piped to vim(1) as pager for man(1), the former sequence
of (Qo \  Qc) renders as "" without the space. Replace with (Qo (space) Qc)
which renders properly in more (all?) pagers.
This commit is contained in:
Devin Teske 2016-02-02 21:58:17 +00:00
parent 677ba8502b
commit 613d7da7d5
1 changed files with 3 additions and 3 deletions
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6
usr.sbin/sysrc/sysrc.8
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@ -1,4 +1,4 @@
.\" Copyright (c) 2011-2015 Devin Teske .\" Copyright (c) 2011-2016 Devin Teske
.\" All rights reserved. .\" All rights reserved.
.\" .\"
.\" Redistribution and use in source and binary forms, with or without .\" Redistribution and use in source and binary forms, with or without
@ -24,7 +24,7 @@
.\" .\"
.\" $FreeBSD$ .\" $FreeBSD$
.\" .\"
.Dd September 12, 2015 .Dd February 2, 2016
.Dt SYSRC 8 .Dt SYSRC 8
.Os .Os
.Sh NAME .Sh NAME
@ -255,7 +255,7 @@ When using the
.Ql key+=value .Ql key+=value
syntax to add items to existing values, syntax to add items to existing values,
the first character of the value is taken as the delimiter separating items the first character of the value is taken as the delimiter separating items
.Pq usually Qo \ Qc or Qo , Qc . .Pq usually Qo (space) Qc or Qo , Qc .
For example, in the following statement: For example, in the following statement:
.Bl -item -offset indent .Bl -item -offset indent
.It .It