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Replace (Qo \ Qc) with (Qo (space) Qc)

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When using col(1) piped to vim(1) as pager for man(1), the former sequence
of (Qo \  Qc) renders as "" without the space. Replace with (Qo (space) Qc)
which renders properly in more (all?) pagers.
This commit is contained in:
Devin Teske 2016-02-02 21:58:17 +00:00
parent 677ba8502b
commit 613d7da7d5
1 changed files with 3 additions and 3 deletions
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6
usr.sbin/sysrc/sysrc.8
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@ -1,4 +1,4 @@
.\" Copyright (c) 2011-2015 Devin Teske
.\" Copyright (c) 2011-2016 Devin Teske
.\" All rights reserved.
.\"
.\" Redistribution and use in source and binary forms, with or without
@ -24,7 +24,7 @@
.\"
.\" $FreeBSD$
.\"
.Dd September 12, 2015
.Dd February 2, 2016
.Dt SYSRC 8
.Os
.Sh NAME
@ -255,7 +255,7 @@ When using the
.Ql key+=value
syntax to add items to existing values,
the first character of the value is taken as the delimiter separating items
.Pq usually Qo \ Qc or Qo , Qc .
.Pq usually Qo (space) Qc or Qo , Qc .
For example, in the following statement:
.Bl -item -offset indent
.It