The dependency chain for priority-inheritance mutexes could be
subverted by userspace into cycle. Both umtx_propagate_priority() and umtx_repropagate_priority() would then loop infinitely, owning the spinlock. Check for the cycle using standard Floyd' algorithm before doing the pass in the affected functions. Add simple check for condition of tricking the thread into a wait for itself, which could be easily simulated by usermode without race. Found by: Eric van Gyzen <eric@vangyzen.net> In collaboration with: Eric van Gyzen <eric@vangyzen.net> Tested by: pho MFC after: 1 week
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@ -1302,6 +1302,47 @@ umtx_pi_adjust_thread(struct umtx_pi *pi, struct thread *td)
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return (1);
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}
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static struct umtx_pi *
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umtx_pi_next(struct umtx_pi *pi)
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{
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struct umtx_q *uq_owner;
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if (pi->pi_owner == NULL)
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return (NULL);
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uq_owner = pi->pi_owner->td_umtxq;
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if (uq_owner == NULL)
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return (NULL);
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return (uq_owner->uq_pi_blocked);
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}
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/*
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* Floyd's Cycle-Finding Algorithm.
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*/
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static bool
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umtx_pi_check_loop(struct umtx_pi *pi)
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{
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struct umtx_pi *pi1; /* fast iterator */
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mtx_assert(&umtx_lock, MA_OWNED);
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if (pi == NULL)
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return (false);
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pi1 = pi;
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for (;;) {
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pi = umtx_pi_next(pi);
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if (pi == NULL)
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break;
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pi1 = umtx_pi_next(pi1);
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if (pi1 == NULL)
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break;
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pi1 = umtx_pi_next(pi1);
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if (pi1 == NULL)
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break;
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if (pi == pi1)
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return (true);
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}
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return (false);
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}
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/*
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* Propagate priority when a thread is blocked on POSIX
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* PI mutex.
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@ -1319,6 +1360,8 @@ umtx_propagate_priority(struct thread *td)
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pi = uq->uq_pi_blocked;
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if (pi == NULL)
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return;
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if (umtx_pi_check_loop(pi))
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return;
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for (;;) {
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td = pi->pi_owner;
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@ -1362,6 +1405,8 @@ umtx_repropagate_priority(struct umtx_pi *pi)
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mtx_assert(&umtx_lock, MA_OWNED);
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if (umtx_pi_check_loop(pi))
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return;
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while (pi != NULL && pi->pi_owner != NULL) {
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pri = PRI_MAX;
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uq_owner = pi->pi_owner->td_umtxq;
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@ -1694,6 +1739,11 @@ do_lock_pi(struct thread *td, struct umutex *m, uint32_t flags,
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continue;
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}
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if ((owner & ~UMUTEX_CONTESTED) == id) {
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error = EDEADLK;
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break;
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}
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if (try != 0) {
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error = EBUSY;
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break;
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