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tests/sys/audit: fix timeout calculation

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This changes the behaviour to a 30s total timeout (needed when running
on slow emulated uniprocessor systems) and timing out after 10s without
any input. This also uses timespecsub() instead of ignoring the
nanoseconds field.

After this change the tests runs more reliably on QEMU and time out less
frequently.

Reviewed By:	asomers
Differential Revision: https://reviews.freebsd.org/D28391
This commit is contained in:
Alex Richardson 2021-01-28 17:23:27 +00:00
parent 83ff5d5d98
commit 869cc06480
1 changed files with 8 additions and 3 deletions
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11
tests/sys/audit/utils.c
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@ -146,13 +146,18 @@ check_auditpipe(struct pollfd fd[], const char *auditregex, FILE *pipestream)
/* Set the expire time for poll(2) while waiting for syscall audit */
ATF_REQUIRE_EQ(0, clock_gettime(CLOCK_MONOTONIC, &endtime));
endtime.tv_sec += 10;
timeout.tv_nsec = endtime.tv_nsec;
/* Set limit to 30 seconds total and ~10s without an event. */
endtime.tv_sec += 30;
for (;;) {
/* Update the time left for auditpipe to return any event */
ATF_REQUIRE_EQ(0, clock_gettime(CLOCK_MONOTONIC, &currtime));
timeout.tv_sec = endtime.tv_sec - currtime.tv_sec;
timespecsub(&endtime, &currtime, &timeout);
timeout.tv_sec = MIN(timeout.tv_sec, 9);
if (timeout.tv_sec < 0) {
atf_tc_fail("%s not found in auditpipe within the "
"time limit", auditregex);
}
switch (ppoll(fd, 1, &timeout, NULL)) {
/* ppoll(2) returns, check if it's what we want */