Fix kenv behavior when there is no static environment
In case where there are no static kernel environment entries, the function init_dynamic_kenv() adds an incorrect entry at position 0 of the dynamic kernel environment. This in turn causes kenv(1) to print and empty list even though there are dynamic entries added later. Fix this by checking env_pos in init_dynamic_kenv() and adding dynamic entries only if there are static entries.
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8b20292658
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@ -231,20 +231,23 @@ init_dynamic_kenv(void *data __unused)
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kenvp = malloc((KENV_SIZE + 1) * sizeof(char *), M_KENV,
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M_WAITOK | M_ZERO);
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i = 0;
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for (cp = kern_envp; cp != NULL; cp = kernenv_next(cp)) {
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len = strlen(cp) + 1;
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if (len > KENV_MNAMELEN + 1 + KENV_MVALLEN + 1) {
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printf("WARNING: too long kenv string, ignoring %s\n",
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cp);
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continue;
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if (env_pos > 0) {
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for (cp = kern_envp; cp != NULL; cp = kernenv_next(cp)) {
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len = strlen(cp) + 1;
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if (len > KENV_MNAMELEN + 1 + KENV_MVALLEN + 1) {
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printf(
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"WARNING: too long kenv string, ignoring %s\n",
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cp);
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continue;
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}
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if (i < KENV_SIZE) {
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kenvp[i] = malloc(len, M_KENV, M_WAITOK);
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strcpy(kenvp[i++], cp);
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} else
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printf(
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"WARNING: too many kenv strings, ignoring %s\n",
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cp);
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}
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if (i < KENV_SIZE) {
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kenvp[i] = malloc(len, M_KENV, M_WAITOK);
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strcpy(kenvp[i++], cp);
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} else
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printf(
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"WARNING: too many kenv strings, ignoring %s\n",
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cp);
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}
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kenvp[i] = NULL;
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