Type of the interrupt handlers on x86 cannot be expressed in C.
Simplify and unify placeholder type definitions. Reviewed by: jhb Sponsored by: The FreeBSD Foundation Differential revision: https://reviews.freebsd.org/D5771
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@ -83,7 +83,7 @@
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#ifndef LOCORE
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typedef void inthand_t(u_int cs, u_int ef, u_int esp, u_int ss);
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typedef void inthand_t(void);
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#define IDTVEC(name) __CONCAT(X,name)
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@ -36,9 +36,6 @@
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extern uint64_t *vm_page_dump;
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/* XXX */
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typedef void alias_for_inthand_t(u_int cs, u_int ef, u_int esp, u_int ss);
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struct savefpu;
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void amd64_db_resume_dbreg(void);
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@ -83,7 +83,7 @@
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#ifndef LOCORE
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typedef void inthand_t(u_int cs, u_int ef, u_int esp, u_int ss);
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typedef void inthand_t(void);
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#define IDTVEC(name) __CONCAT(X,name)
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@ -46,7 +46,6 @@ extern int szosigcode;
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#endif
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extern uint32_t *vm_page_dump;
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typedef void alias_for_inthand_t(u_int cs, u_int ef, u_int esp, u_int ss);
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struct segment_descriptor;
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union savefpu;
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@ -86,6 +86,13 @@ struct fpreg;
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struct dbreg;
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struct dumperinfo;
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/*
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* The interface type of the interrupt handler entry point cannot be
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* expressed in C. Use simplest non-variadic function type as an
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* approximation.
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*/
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typedef void alias_for_inthand_t(void);
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void *alloc_fpusave(int flags);
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void busdma_swi(void);
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bool cpu_mwait_usable(void);
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