Register the interrupt handler at the end of wi_attach rather than at
the beginning. There's a race in the shared interrutp case. If another interrupt happens after the interrupt is setup, then we'd try to lock an uninitialized mutex. In addition, if we bailed out due to a too old version of firmware, we'd leave the interrupt enabled with all the fun that ensues....
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parent
b834665cd5
commit
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@ -250,19 +250,6 @@ wi_attach(device_t dev)
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}
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}
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ic = ifp->if_l2com;
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ic = ifp->if_l2com;
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/*
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* NB: no locking is needed here; don't put it here
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* unless you can prove it!
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*/
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error = bus_setup_intr(dev, sc->irq, INTR_TYPE_NET | INTR_MPSAFE,
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NULL, wi_intr, sc, &sc->wi_intrhand);
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if (error) {
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device_printf(dev, "bus_setup_intr() failed! (%d)\n", error);
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wi_free(dev);
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return error;
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}
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sc->sc_firmware_type = WI_NOTYPE;
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sc->sc_firmware_type = WI_NOTYPE;
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sc->wi_cmd_count = 500;
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sc->wi_cmd_count = 500;
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/* Reset the NIC. */
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/* Reset the NIC. */
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@ -473,6 +460,17 @@ wi_attach(device_t dev)
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if (bootverbose)
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if (bootverbose)
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ieee80211_announce(ic);
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ieee80211_announce(ic);
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error = bus_setup_intr(dev, sc->irq, INTR_TYPE_NET | INTR_MPSAFE,
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NULL, wi_intr, sc, &sc->wi_intrhand);
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if (error) {
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device_printf(dev, "bus_setup_intr() failed! (%d)\n", error);
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bpfdetach(ifp);
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ieee80211_ifdetach(ic);
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if_free(sc->sc_ifp);
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wi_free(dev);
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return error;
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}
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return (0);
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return (0);
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}
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}
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