David Schultz 92a1a6e169 Fix some corner cases:
- fma(x, y, z) returns z, not NaN, if z is infinite, x and y are finite,
  x*y overflows, and x*y and z have opposite signs.
- fma(x, y, z) doesn't generate an overflow, underflow, or inexact exception
  if z is NaN or infinite, as per IEEE 754R.
- If the rounding mode is set to FE_DOWNWARD, fma(1.0, 0.0, -0.0) is -0.0,
  not +0.0.
2008-04-03 06:14:51 +00:00
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