freebsd-skq/usr.sbin/pmcstudy/eval_expr.c
Warner Losh 52467047aa Regularize the Netflix copyright
Use recent best practices for Copyright form at the top of
the license:
1. Remove all the All Rights Reserved clauses on our stuff. Where we
   piggybacked others, use a separate line to make things clear.
2. Use "Netflix, Inc." everywhere.
3. Use a single line for the copyright for grep friendliness.
4. Use date ranges in all places for our stuff.

Approved by: Netflix Legal (who gave me the form), adrian@ (pmc files)
2019-02-04 21:28:25 +00:00

717 lines
16 KiB
C

/*-
* Copyright (c) 2015 Netflix, Inc.
*
* Redistribution and use in source and binary forms, with or without
* modification, are permitted provided that the following conditions
* are met:
* 1. Redistributions of source code must retain the above copyright
* notice, this list of conditions and the following disclaimer,
* in this position and unchanged.
* 2. Redistributions in binary form must reproduce the above copyright
* notice, this list of conditions and the following disclaimer in the
* documentation and/or other materials provided with the distribution.
* 3. The name of the author may not be used to endorse or promote products
* derived from this software without specific prior written permission
*
* THIS SOFTWARE IS PROVIDED BY THE AUTHOR ``AS IS'' AND ANY EXPRESS OR
* IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED WARRANTIES
* OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE ARE DISCLAIMED.
* IN NO EVENT SHALL THE AUTHOR BE LIABLE FOR ANY DIRECT, INDIRECT,
* INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT
* NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE,
* DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY
* THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT
* (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF
* THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
*/
#include <sys/types.h>
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <string.h>
#include <strings.h>
#include <ctype.h>
#include "eval_expr.h"
__FBSDID("$FreeBSD$");
static struct expression *
alloc_and_hook_expr(struct expression **exp_p, struct expression **last_p)
{
struct expression *ex, *at;
ex = malloc(sizeof(struct expression));
if (ex == NULL) {
printf("Out of memory in exp allocation\n");
exit(-2);
}
memset(ex, 0, sizeof(struct expression));
if (*exp_p == NULL) {
*exp_p = ex;
}
at = *last_p;
if (at == NULL) {
/* First one, its last */
*last_p = ex;
} else {
/* Chain it to the end and update last */
at->next = ex;
ex->prev = at;
*last_p = ex;
}
return (ex);
}
static int
validate_expr(struct expression *exp, int val1_is_set, int op_is_set, int val2_is_set,
int *op_cnt)
{
int val1, op, val2;
int open_cnt;
val1 = op = val2 = 0;
if (val1_is_set) {
val1 = 1;
}
if (op_is_set) {
op = 1;
}
if (val2_is_set) {
val2 = 1;
}
open_cnt = *op_cnt;
if (exp == NULL) {
/* End of the road */
if (val1 && op && val2 && (open_cnt == 0)) {
return(0);
} else {
return(1);
}
}
switch(exp->type) {
case TYPE_OP_PLUS:
case TYPE_OP_MINUS:
case TYPE_OP_MULT:
case TYPE_OP_DIVIDE:
if (val1 && op && val2) {
/* We are at x + y +
* collapse back to val/op
*/
val1 = 1;
op = 1;
val2 = 0;
} else if ((op == 0) && (val1)) {
op = 1;
} else {
printf("Op but no val1 set\n");
return(-1);
}
break;
case TYPE_PARN_OPEN:
if (exp->next == NULL) {
printf("NULL after open paren\n");
exit(-1);
}
if ((exp->next->type == TYPE_OP_PLUS) ||
(exp->next->type == TYPE_OP_MINUS) ||
(exp->next->type == TYPE_OP_DIVIDE) ||
(exp->next->type == TYPE_OP_MULT)) {
printf("'( OP' -- not allowed\n");
return(-1);
}
if (val1 && (op == 0)) {
printf("'Val (' -- not allowed\n");
return(-1);
}
if (val1 && op && val2) {
printf("'Val OP Val (' -- not allowed\n");
return(-1);
}
open_cnt++;
*op_cnt = open_cnt;
if (val1) {
if (validate_expr(exp->next, 0, 0, 0, op_cnt) == 0) {
val2 = 1;
} else {
return(-1);
}
} else {
return(validate_expr(exp->next, 0, 0, 0, op_cnt));
}
break;
case TYPE_PARN_CLOSE:
open_cnt--;
*op_cnt = open_cnt;
if (val1 && op && val2) {
return(0);
} else {
printf("Found close paren and not complete\n");
return(-1);
}
break;
case TYPE_VALUE_CON:
case TYPE_VALUE_PMC:
if (val1 == 0) {
val1 = 1;
} else if (val1 && op) {
val2 = 1;
} else {
printf("val1 set, val2 about to be set op empty\n");
return(-1);
}
break;
default:
printf("unknown type %d\n", exp->type);
exit(-5);
break;
}
return(validate_expr(exp->next, val1, op, val2, op_cnt));
}
void
print_exp(struct expression *exp)
{
if (exp == NULL) {
printf("\n");
return;
}
switch(exp->type) {
case TYPE_OP_PLUS:
printf(" + ");
break;
case TYPE_OP_MINUS:
printf(" - ");
break;
case TYPE_OP_MULT:
printf(" * ");
break;
case TYPE_OP_DIVIDE:
printf(" / ");
break;
case TYPE_PARN_OPEN:
printf(" ( ");
break;
case TYPE_PARN_CLOSE:
printf(" ) ");
break;
case TYPE_VALUE_CON:
printf("%f", exp->value);
break;
case TYPE_VALUE_PMC:
printf("%s", exp->name);
break;
default:
printf("Unknown op %d\n", exp->type);
break;
}
print_exp(exp->next);
}
static void
walk_back_and_insert_paren(struct expression **beg, struct expression *frm)
{
struct expression *at, *ex;
/* Setup our new open paren */
ex = malloc(sizeof(struct expression));
if (ex == NULL) {
printf("Out of memory in exp allocation\n");
exit(-2);
}
memset(ex, 0, sizeof(struct expression));
ex->type = TYPE_PARN_OPEN;
/* Now lets place it */
at = frm->prev;
if (at == *beg) {
/* We are inserting at the head of the list */
in_beg:
ex->next = at;
at->prev = ex;
*beg = ex;
return;
} else if ((at->type == TYPE_VALUE_CON) ||
(at->type == TYPE_VALUE_PMC)) {
/* Simple case we have a value in the previous position */
in_mid:
ex->prev = at->prev;
ex->prev->next = ex;
ex->next = at;
at->prev = ex;
return;
} else if (at->type == TYPE_PARN_CLOSE) {
/* Skip through until we reach beg or all ( closes */
int par_cnt=1;
at = at->prev;
while(par_cnt) {
if (at->type == TYPE_PARN_CLOSE) {
par_cnt++;
} else if (at->type == TYPE_PARN_OPEN) {
par_cnt--;
if (par_cnt == 0) {
break;
}
}
at = at->prev;
}
if (at == *beg) {
/* At beginning we insert */
goto in_beg;
} else {
goto in_mid;
}
} else {
printf("%s:Unexpected type:%d?\n",
__FUNCTION__, at->type);
exit(-1);
}
}
static void
walk_fwd_and_insert_paren(struct expression *frm, struct expression **added)
{
struct expression *at, *ex;
/* Setup our new close paren */
ex = malloc(sizeof(struct expression));
if (ex == NULL) {
printf("Out of memory in exp allocation\n");
exit(-2);
}
memset(ex, 0, sizeof(struct expression));
ex->type = TYPE_PARN_CLOSE;
*added = ex;
/* Now lets place it */
at = frm->next;
if ((at->type == TYPE_VALUE_CON) ||
(at->type == TYPE_VALUE_PMC)) {
/* Simple case we have a value in the previous position */
insertit:
ex->next = at->next;
ex->prev = at;
at->next = ex;
return;
} else if (at->type == TYPE_PARN_OPEN) {
int par_cnt=1;
at = at->next;
while(par_cnt) {
if (at->type == TYPE_PARN_OPEN) {
par_cnt++;
} else if (at->type == TYPE_PARN_CLOSE) {
par_cnt--;
if (par_cnt == 0) {
break;
}
}
at = at->next;
}
goto insertit;
} else {
printf("%s:Unexpected type:%d?\n",
__FUNCTION__,
at->type);
exit(-1);
}
}
static void
add_precendence(struct expression **beg, struct expression *start, struct expression *end)
{
/*
* Between start and end add () around any * or /. This
* is quite tricky since if there is a () set inside the
* list we need to skip over everything in the ()'s considering
* that just a value.
*/
struct expression *at, *newone;
int open_cnt;
at = start;
open_cnt = 0;
while(at != end) {
if (at->type == TYPE_PARN_OPEN) {
open_cnt++;
}
if (at->type == TYPE_PARN_CLOSE) {
open_cnt--;
}
if (open_cnt == 0) {
if ((at->type == TYPE_OP_MULT) ||
(at->type == TYPE_OP_DIVIDE)) {
walk_back_and_insert_paren(beg, at);
walk_fwd_and_insert_paren(at, &newone);
at = newone->next;
continue;
}
}
at = at->next;
}
}
static void
set_math_precidence(struct expression **beg, struct expression *exp, struct expression **stopped)
{
struct expression *at, *start, *end;
int cnt_lower, cnt_upper;
/*
* Walk through and set any math precedence to
* get proper precedence we insert () around * / over + -
*/
end = NULL;
start = at = exp;
cnt_lower = cnt_upper = 0;
while(at) {
if (at->type == TYPE_PARN_CLOSE) {
/* Done with that paren */
if (stopped) {
*stopped = at;
}
if (cnt_lower && cnt_upper) {
/* We have a mixed set ... add precedence between start/end */
add_precendence(beg, start, end);
}
return;
}
if (at->type == TYPE_PARN_OPEN) {
set_math_precidence(beg, at->next, &end);
at = end;
continue;
} else if ((at->type == TYPE_OP_PLUS) ||
(at->type == TYPE_OP_MINUS)) {
cnt_lower++;
} else if ((at->type == TYPE_OP_DIVIDE) ||
(at->type == TYPE_OP_MULT)) {
cnt_upper++;
}
at = at->next;
}
if (cnt_lower && cnt_upper) {
add_precendence(beg, start, NULL);
}
}
extern char **valid_pmcs;
extern int valid_pmc_cnt;
static void
pmc_name_set(struct expression *at)
{
int i, idx, fnd;
if (at->name[0] == '%') {
/* Special number after $ gives index */
idx = strtol(&at->name[1], NULL, 0);
if (idx >= valid_pmc_cnt) {
printf("Unknown PMC %s -- largest we have is $%d -- can't run your expression\n",
at->name, valid_pmc_cnt);
exit(-1);
}
strcpy(at->name, valid_pmcs[idx]);
} else {
for(i=0, fnd=0; i<valid_pmc_cnt; i++) {
if (strcmp(valid_pmcs[i], at->name) == 0) {
fnd = 1;
break;
}
}
if (!fnd) {
printf("PMC %s does not exist on this machine -- can't run your expression\n",
at->name);
exit(-1);
}
}
}
struct expression *
parse_expression(char *str)
{
struct expression *exp=NULL, *last=NULL, *at;
int open_par, close_par;
int op_cnt=0;
size_t siz, i, x;
/*
* Walk through a string expression and convert
* it to a linked list of actions. We do this by:
* a) Counting the open/close paren's, there must
* be a matching number.
* b) If we have balanced paren's then create a linked list
* of the operators, then we validate that expression further.
* c) Validating that we have:
* val OP val <or>
* val OP ( <and>
* inside every paran you have a:
* val OP val <or>
* val OP ( <recursively>
* d) A final optional step (not implemented yet) would be
* to insert the mathematical precedence paran's. For
* the start we will just do the left to right evaluation and
* then later we can add this guy to add paran's to make it
* mathimatically correct... i.e instead of 1 + 2 * 3 we
* would translate it into 1 + ( 2 * 3).
*/
open_par = close_par = 0;
siz = strlen(str);
/* No trailing newline please */
if (str[(siz-1)] == '\n') {
str[(siz-1)] = 0;
siz--;
}
for(i=0; i<siz; i++) {
if (str[i] == '(') {
open_par++;
} else if (str[i] == ')') {
close_par++;
}
}
if (open_par != close_par) {
printf("Invalid expression '%s' %d open paren's and %d close?\n",
str, open_par, close_par);
exit(-1);
}
for(i=0; i<siz; i++) {
if (str[i] == '(') {
at = alloc_and_hook_expr(&exp, &last);
at->type = TYPE_PARN_OPEN;
} else if (str[i] == ')') {
at = alloc_and_hook_expr(&exp, &last);
at->type = TYPE_PARN_CLOSE;
} else if (str[i] == ' ') {
/* Extra blank */
continue;
} else if (str[i] == '\t') {
/* Extra tab */
continue;
} else if (str[i] == '+') {
at = alloc_and_hook_expr(&exp, &last);
at->type = TYPE_OP_PLUS;
} else if (str[i] == '-') {
at = alloc_and_hook_expr(&exp, &last);
at->type = TYPE_OP_MINUS;
} else if (str[i] == '/') {
at = alloc_and_hook_expr(&exp, &last);
at->type = TYPE_OP_DIVIDE;
} else if (str[i] == '*') {
at = alloc_and_hook_expr(&exp, &last);
at->type = TYPE_OP_MULT;
} else {
/* Its a value or PMC constant */
at = alloc_and_hook_expr(&exp, &last);
if (isdigit(str[i]) || (str[i] == '.')) {
at->type = TYPE_VALUE_CON;
} else {
at->type = TYPE_VALUE_PMC;
}
x = 0;
while ((str[i] != ' ') &&
(str[i] != '\t') &&
(str[i] != 0) &&
(str[i] != ')') &&
(str[i] != '(')) {
/* We collect the constant until a space or tab */
at->name[x] = str[i];
i++;
x++;
if (x >=(sizeof(at->name)-1)) {
printf("Value/Constant too long %d max:%d\n",
(int)x, (int)(sizeof(at->name)-1));
exit(-3);
}
}
if (str[i] != 0) {
/* Need to back up and see the last char since
* the for will increment the loop.
*/
i--;
}
/* Now we have pulled the string, set it up */
if (at->type == TYPE_VALUE_CON) {
at->state = STATE_FILLED;
at->value = strtod(at->name, NULL);
} else {
pmc_name_set(at);
}
}
}
/* Now lets validate its a workable expression */
if (validate_expr(exp, 0, 0, 0, &op_cnt)) {
printf("Invalid expression\n");
exit(-4);
}
set_math_precidence(&exp, exp, NULL);
return (exp);
}
static struct expression *
gather_exp_to_paren_close(struct expression *exp, double *val_fill)
{
/*
* I have been given ( ???
* so I could see either
* (
* or
* Val Op
*
*/
struct expression *lastproc;
double val;
if (exp->type == TYPE_PARN_OPEN) {
lastproc = gather_exp_to_paren_close(exp->next, &val);
*val_fill = val;
} else {
*val_fill = run_expr(exp, 0, &lastproc);
}
return(lastproc);
}
double
run_expr(struct expression *exp, int initial_call, struct expression **lastone)
{
/*
* We expect to find either
* a) A Open Paren
* or
* b) Val-> Op -> Val
* or
* c) Val-> Op -> Open Paren
*/
double val1, val2, res;
struct expression *op, *other_half, *rest;
if (exp->type == TYPE_PARN_OPEN) {
op = gather_exp_to_paren_close(exp->next, &val1);
} else if(exp->type == TYPE_VALUE_CON) {
val1 = exp->value;
op = exp->next;
} else if (exp->type == TYPE_VALUE_PMC) {
val1 = exp->value;
op = exp->next;
} else {
printf("Illegal value in %s huh?\n", __FUNCTION__);
exit(-1);
}
if (op == NULL) {
return (val1);
}
more_to_do:
other_half = op->next;
if (other_half->type == TYPE_PARN_OPEN) {
rest = gather_exp_to_paren_close(other_half->next, &val2);
} else if(other_half->type == TYPE_VALUE_CON) {
val2 = other_half->value;
rest = other_half->next;
} else if (other_half->type == TYPE_VALUE_PMC) {
val2 = other_half->value;
rest = other_half->next;
} else {
printf("Illegal2 value in %s huh?\n", __FUNCTION__);
exit(-1);
}
switch(op->type) {
case TYPE_OP_PLUS:
res = val1 + val2;
break;
case TYPE_OP_MINUS:
res = val1 - val2;
break;
case TYPE_OP_MULT:
res = val1 * val2;
break;
case TYPE_OP_DIVIDE:
if (val2 != 0.0)
res = val1 / val2;
else {
printf("Division by zero averted\n");
res = 1.0;
}
break;
default:
printf("Op is not an operator -- its %d\n",
op->type);
exit(-1);
break;
}
if (rest == NULL) {
if (lastone) {
*lastone = NULL;
}
return (res);
}
if ((rest->type == TYPE_PARN_CLOSE) && (initial_call == 0)) {
if (lastone) {
*lastone = rest->next;
}
return(res);
}
/* There is more, as in
* a + b + c
* where we just did a + b
* so now it becomes val1 is set to res and
* we need to proceed with the rest of it.
*/
val1 = res;
op = rest;
if ((op->type != TYPE_OP_PLUS) &&
(op->type != TYPE_OP_MULT) &&
(op->type != TYPE_OP_MINUS) &&
(op->type != TYPE_OP_DIVIDE)) {
printf("%s ending on type:%d not an op??\n", __FUNCTION__, op->type);
return(res);
}
if (op)
goto more_to_do;
return (res);
}
#ifdef STAND_ALONE_TESTING
static double
calc_expr(struct expression *exp)
{
struct expression *at;
double xx;
/* First clear PMC's setting */
for(at = exp; at != NULL; at = at->next) {
if (at->type == TYPE_VALUE_PMC) {
at->state = STATE_UNSET;
}
}
/* Now for all pmc's make up values .. here is where I would pull them */
for(at = exp; at != NULL; at = at->next) {
if (at->type == TYPE_VALUE_PMC) {
at->value = (random() * 1.0);
at->state = STATE_FILLED;
if (at->value == 0.0) {
/* So we don't have div by 0 */
at->value = 1.0;
}
}
}
/* Now lets calculate the expression */
print_exp(exp);
xx = run_expr(exp, 1, NULL);
printf("Answer is %f\n", xx);
return(xx);
}
int
main(int argc, char **argv)
{
struct expression *exp;
if (argc < 2) {
printf("Use %s expression\n", argv[0]);
return(-1);
}
exp = parse_expression(argv[1]);
printf("Now the calc\n");
calc_expr(exp);
return(0);
}
#endif