52467047aa
Use recent best practices for Copyright form at the top of the license: 1. Remove all the All Rights Reserved clauses on our stuff. Where we piggybacked others, use a separate line to make things clear. 2. Use "Netflix, Inc." everywhere. 3. Use a single line for the copyright for grep friendliness. 4. Use date ranges in all places for our stuff. Approved by: Netflix Legal (who gave me the form), adrian@ (pmc files)
717 lines
16 KiB
C
717 lines
16 KiB
C
/*-
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* Copyright (c) 2015 Netflix, Inc.
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*
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* Redistribution and use in source and binary forms, with or without
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* modification, are permitted provided that the following conditions
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* are met:
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* 1. Redistributions of source code must retain the above copyright
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* notice, this list of conditions and the following disclaimer,
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* in this position and unchanged.
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* 2. Redistributions in binary form must reproduce the above copyright
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* notice, this list of conditions and the following disclaimer in the
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* documentation and/or other materials provided with the distribution.
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* 3. The name of the author may not be used to endorse or promote products
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* derived from this software without specific prior written permission
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*
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* THIS SOFTWARE IS PROVIDED BY THE AUTHOR ``AS IS'' AND ANY EXPRESS OR
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* IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED WARRANTIES
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* OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE ARE DISCLAIMED.
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* IN NO EVENT SHALL THE AUTHOR BE LIABLE FOR ANY DIRECT, INDIRECT,
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* INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT
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* NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE,
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* DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY
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* THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT
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* (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF
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* THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
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*/
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#include <sys/types.h>
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#include <stdio.h>
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#include <stdlib.h>
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#include <unistd.h>
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#include <string.h>
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#include <strings.h>
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#include <ctype.h>
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#include "eval_expr.h"
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__FBSDID("$FreeBSD$");
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static struct expression *
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alloc_and_hook_expr(struct expression **exp_p, struct expression **last_p)
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{
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struct expression *ex, *at;
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ex = malloc(sizeof(struct expression));
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if (ex == NULL) {
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printf("Out of memory in exp allocation\n");
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exit(-2);
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}
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memset(ex, 0, sizeof(struct expression));
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if (*exp_p == NULL) {
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*exp_p = ex;
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}
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at = *last_p;
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if (at == NULL) {
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/* First one, its last */
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*last_p = ex;
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} else {
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/* Chain it to the end and update last */
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at->next = ex;
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ex->prev = at;
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*last_p = ex;
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}
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return (ex);
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}
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static int
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validate_expr(struct expression *exp, int val1_is_set, int op_is_set, int val2_is_set,
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int *op_cnt)
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{
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int val1, op, val2;
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int open_cnt;
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val1 = op = val2 = 0;
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if (val1_is_set) {
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val1 = 1;
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}
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if (op_is_set) {
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op = 1;
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}
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if (val2_is_set) {
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val2 = 1;
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}
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open_cnt = *op_cnt;
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if (exp == NULL) {
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/* End of the road */
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if (val1 && op && val2 && (open_cnt == 0)) {
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return(0);
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} else {
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return(1);
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}
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}
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switch(exp->type) {
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case TYPE_OP_PLUS:
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case TYPE_OP_MINUS:
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case TYPE_OP_MULT:
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case TYPE_OP_DIVIDE:
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if (val1 && op && val2) {
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/* We are at x + y +
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* collapse back to val/op
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*/
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val1 = 1;
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op = 1;
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val2 = 0;
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} else if ((op == 0) && (val1)) {
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op = 1;
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} else {
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printf("Op but no val1 set\n");
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return(-1);
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}
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break;
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case TYPE_PARN_OPEN:
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if (exp->next == NULL) {
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printf("NULL after open paren\n");
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exit(-1);
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}
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if ((exp->next->type == TYPE_OP_PLUS) ||
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(exp->next->type == TYPE_OP_MINUS) ||
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(exp->next->type == TYPE_OP_DIVIDE) ||
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(exp->next->type == TYPE_OP_MULT)) {
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printf("'( OP' -- not allowed\n");
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return(-1);
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}
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if (val1 && (op == 0)) {
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printf("'Val (' -- not allowed\n");
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return(-1);
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}
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if (val1 && op && val2) {
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printf("'Val OP Val (' -- not allowed\n");
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return(-1);
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}
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open_cnt++;
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*op_cnt = open_cnt;
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if (val1) {
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if (validate_expr(exp->next, 0, 0, 0, op_cnt) == 0) {
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val2 = 1;
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} else {
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return(-1);
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}
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} else {
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return(validate_expr(exp->next, 0, 0, 0, op_cnt));
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}
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break;
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case TYPE_PARN_CLOSE:
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open_cnt--;
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*op_cnt = open_cnt;
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if (val1 && op && val2) {
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return(0);
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} else {
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printf("Found close paren and not complete\n");
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return(-1);
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}
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break;
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case TYPE_VALUE_CON:
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case TYPE_VALUE_PMC:
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if (val1 == 0) {
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val1 = 1;
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} else if (val1 && op) {
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val2 = 1;
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} else {
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printf("val1 set, val2 about to be set op empty\n");
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return(-1);
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}
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break;
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default:
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printf("unknown type %d\n", exp->type);
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exit(-5);
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break;
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}
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return(validate_expr(exp->next, val1, op, val2, op_cnt));
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}
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void
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print_exp(struct expression *exp)
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{
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if (exp == NULL) {
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printf("\n");
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return;
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}
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switch(exp->type) {
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case TYPE_OP_PLUS:
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printf(" + ");
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break;
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case TYPE_OP_MINUS:
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printf(" - ");
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break;
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case TYPE_OP_MULT:
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printf(" * ");
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break;
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case TYPE_OP_DIVIDE:
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printf(" / ");
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break;
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case TYPE_PARN_OPEN:
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printf(" ( ");
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break;
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case TYPE_PARN_CLOSE:
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printf(" ) ");
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break;
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case TYPE_VALUE_CON:
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printf("%f", exp->value);
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break;
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case TYPE_VALUE_PMC:
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printf("%s", exp->name);
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break;
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default:
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printf("Unknown op %d\n", exp->type);
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break;
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}
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print_exp(exp->next);
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}
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static void
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walk_back_and_insert_paren(struct expression **beg, struct expression *frm)
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{
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struct expression *at, *ex;
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/* Setup our new open paren */
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ex = malloc(sizeof(struct expression));
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if (ex == NULL) {
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printf("Out of memory in exp allocation\n");
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exit(-2);
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}
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memset(ex, 0, sizeof(struct expression));
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ex->type = TYPE_PARN_OPEN;
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/* Now lets place it */
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at = frm->prev;
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if (at == *beg) {
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/* We are inserting at the head of the list */
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in_beg:
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ex->next = at;
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at->prev = ex;
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*beg = ex;
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return;
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} else if ((at->type == TYPE_VALUE_CON) ||
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(at->type == TYPE_VALUE_PMC)) {
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/* Simple case we have a value in the previous position */
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in_mid:
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ex->prev = at->prev;
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ex->prev->next = ex;
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ex->next = at;
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at->prev = ex;
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return;
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} else if (at->type == TYPE_PARN_CLOSE) {
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/* Skip through until we reach beg or all ( closes */
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int par_cnt=1;
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at = at->prev;
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while(par_cnt) {
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if (at->type == TYPE_PARN_CLOSE) {
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par_cnt++;
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} else if (at->type == TYPE_PARN_OPEN) {
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par_cnt--;
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if (par_cnt == 0) {
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break;
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}
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}
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at = at->prev;
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}
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if (at == *beg) {
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/* At beginning we insert */
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goto in_beg;
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} else {
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goto in_mid;
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}
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} else {
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printf("%s:Unexpected type:%d?\n",
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__FUNCTION__, at->type);
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exit(-1);
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}
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}
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static void
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walk_fwd_and_insert_paren(struct expression *frm, struct expression **added)
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{
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struct expression *at, *ex;
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/* Setup our new close paren */
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ex = malloc(sizeof(struct expression));
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if (ex == NULL) {
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printf("Out of memory in exp allocation\n");
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exit(-2);
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}
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memset(ex, 0, sizeof(struct expression));
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ex->type = TYPE_PARN_CLOSE;
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*added = ex;
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/* Now lets place it */
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at = frm->next;
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if ((at->type == TYPE_VALUE_CON) ||
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(at->type == TYPE_VALUE_PMC)) {
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/* Simple case we have a value in the previous position */
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insertit:
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ex->next = at->next;
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ex->prev = at;
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at->next = ex;
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return;
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} else if (at->type == TYPE_PARN_OPEN) {
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int par_cnt=1;
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at = at->next;
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while(par_cnt) {
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if (at->type == TYPE_PARN_OPEN) {
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par_cnt++;
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} else if (at->type == TYPE_PARN_CLOSE) {
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par_cnt--;
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if (par_cnt == 0) {
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break;
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}
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}
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at = at->next;
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}
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goto insertit;
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} else {
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printf("%s:Unexpected type:%d?\n",
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__FUNCTION__,
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at->type);
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exit(-1);
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}
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}
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static void
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add_precendence(struct expression **beg, struct expression *start, struct expression *end)
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{
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/*
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* Between start and end add () around any * or /. This
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* is quite tricky since if there is a () set inside the
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* list we need to skip over everything in the ()'s considering
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* that just a value.
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*/
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struct expression *at, *newone;
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int open_cnt;
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at = start;
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open_cnt = 0;
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while(at != end) {
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if (at->type == TYPE_PARN_OPEN) {
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open_cnt++;
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}
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if (at->type == TYPE_PARN_CLOSE) {
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open_cnt--;
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}
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if (open_cnt == 0) {
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if ((at->type == TYPE_OP_MULT) ||
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(at->type == TYPE_OP_DIVIDE)) {
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walk_back_and_insert_paren(beg, at);
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walk_fwd_and_insert_paren(at, &newone);
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at = newone->next;
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continue;
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}
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}
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at = at->next;
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}
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}
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static void
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set_math_precidence(struct expression **beg, struct expression *exp, struct expression **stopped)
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{
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struct expression *at, *start, *end;
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int cnt_lower, cnt_upper;
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/*
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* Walk through and set any math precedence to
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* get proper precedence we insert () around * / over + -
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*/
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end = NULL;
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start = at = exp;
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cnt_lower = cnt_upper = 0;
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while(at) {
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if (at->type == TYPE_PARN_CLOSE) {
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/* Done with that paren */
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if (stopped) {
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*stopped = at;
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}
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if (cnt_lower && cnt_upper) {
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/* We have a mixed set ... add precedence between start/end */
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add_precendence(beg, start, end);
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}
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return;
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}
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if (at->type == TYPE_PARN_OPEN) {
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set_math_precidence(beg, at->next, &end);
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at = end;
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continue;
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} else if ((at->type == TYPE_OP_PLUS) ||
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(at->type == TYPE_OP_MINUS)) {
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cnt_lower++;
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} else if ((at->type == TYPE_OP_DIVIDE) ||
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(at->type == TYPE_OP_MULT)) {
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cnt_upper++;
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}
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at = at->next;
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}
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if (cnt_lower && cnt_upper) {
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add_precendence(beg, start, NULL);
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}
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}
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extern char **valid_pmcs;
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extern int valid_pmc_cnt;
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static void
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pmc_name_set(struct expression *at)
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{
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int i, idx, fnd;
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if (at->name[0] == '%') {
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/* Special number after $ gives index */
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idx = strtol(&at->name[1], NULL, 0);
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if (idx >= valid_pmc_cnt) {
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printf("Unknown PMC %s -- largest we have is $%d -- can't run your expression\n",
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at->name, valid_pmc_cnt);
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exit(-1);
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}
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strcpy(at->name, valid_pmcs[idx]);
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} else {
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for(i=0, fnd=0; i<valid_pmc_cnt; i++) {
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if (strcmp(valid_pmcs[i], at->name) == 0) {
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fnd = 1;
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break;
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}
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}
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if (!fnd) {
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printf("PMC %s does not exist on this machine -- can't run your expression\n",
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at->name);
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exit(-1);
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}
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}
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}
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struct expression *
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parse_expression(char *str)
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{
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struct expression *exp=NULL, *last=NULL, *at;
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int open_par, close_par;
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int op_cnt=0;
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size_t siz, i, x;
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/*
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* Walk through a string expression and convert
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* it to a linked list of actions. We do this by:
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* a) Counting the open/close paren's, there must
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* be a matching number.
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* b) If we have balanced paren's then create a linked list
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* of the operators, then we validate that expression further.
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* c) Validating that we have:
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* val OP val <or>
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* val OP ( <and>
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* inside every paran you have a:
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* val OP val <or>
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* val OP ( <recursively>
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* d) A final optional step (not implemented yet) would be
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* to insert the mathematical precedence paran's. For
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* the start we will just do the left to right evaluation and
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* then later we can add this guy to add paran's to make it
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* mathimatically correct... i.e instead of 1 + 2 * 3 we
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* would translate it into 1 + ( 2 * 3).
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*/
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open_par = close_par = 0;
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siz = strlen(str);
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/* No trailing newline please */
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if (str[(siz-1)] == '\n') {
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str[(siz-1)] = 0;
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siz--;
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}
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for(i=0; i<siz; i++) {
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if (str[i] == '(') {
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open_par++;
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} else if (str[i] == ')') {
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close_par++;
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}
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}
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if (open_par != close_par) {
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printf("Invalid expression '%s' %d open paren's and %d close?\n",
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str, open_par, close_par);
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exit(-1);
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}
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for(i=0; i<siz; i++) {
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if (str[i] == '(') {
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at = alloc_and_hook_expr(&exp, &last);
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at->type = TYPE_PARN_OPEN;
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} else if (str[i] == ')') {
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at = alloc_and_hook_expr(&exp, &last);
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at->type = TYPE_PARN_CLOSE;
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} else if (str[i] == ' ') {
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/* Extra blank */
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continue;
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} else if (str[i] == '\t') {
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/* Extra tab */
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continue;
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} else if (str[i] == '+') {
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at = alloc_and_hook_expr(&exp, &last);
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at->type = TYPE_OP_PLUS;
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} else if (str[i] == '-') {
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at = alloc_and_hook_expr(&exp, &last);
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at->type = TYPE_OP_MINUS;
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} else if (str[i] == '/') {
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at = alloc_and_hook_expr(&exp, &last);
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at->type = TYPE_OP_DIVIDE;
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} else if (str[i] == '*') {
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at = alloc_and_hook_expr(&exp, &last);
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at->type = TYPE_OP_MULT;
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} else {
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/* Its a value or PMC constant */
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at = alloc_and_hook_expr(&exp, &last);
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if (isdigit(str[i]) || (str[i] == '.')) {
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at->type = TYPE_VALUE_CON;
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} else {
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at->type = TYPE_VALUE_PMC;
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}
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x = 0;
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while ((str[i] != ' ') &&
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(str[i] != '\t') &&
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(str[i] != 0) &&
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(str[i] != ')') &&
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(str[i] != '(')) {
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/* We collect the constant until a space or tab */
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at->name[x] = str[i];
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i++;
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x++;
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if (x >=(sizeof(at->name)-1)) {
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printf("Value/Constant too long %d max:%d\n",
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(int)x, (int)(sizeof(at->name)-1));
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exit(-3);
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}
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}
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if (str[i] != 0) {
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/* Need to back up and see the last char since
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* the for will increment the loop.
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*/
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i--;
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}
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/* Now we have pulled the string, set it up */
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if (at->type == TYPE_VALUE_CON) {
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at->state = STATE_FILLED;
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at->value = strtod(at->name, NULL);
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} else {
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|
pmc_name_set(at);
|
|
}
|
|
}
|
|
}
|
|
/* Now lets validate its a workable expression */
|
|
if (validate_expr(exp, 0, 0, 0, &op_cnt)) {
|
|
printf("Invalid expression\n");
|
|
exit(-4);
|
|
}
|
|
set_math_precidence(&exp, exp, NULL);
|
|
return (exp);
|
|
}
|
|
|
|
|
|
|
|
static struct expression *
|
|
gather_exp_to_paren_close(struct expression *exp, double *val_fill)
|
|
{
|
|
/*
|
|
* I have been given ( ???
|
|
* so I could see either
|
|
* (
|
|
* or
|
|
* Val Op
|
|
*
|
|
*/
|
|
struct expression *lastproc;
|
|
double val;
|
|
|
|
if (exp->type == TYPE_PARN_OPEN) {
|
|
lastproc = gather_exp_to_paren_close(exp->next, &val);
|
|
*val_fill = val;
|
|
} else {
|
|
*val_fill = run_expr(exp, 0, &lastproc);
|
|
}
|
|
return(lastproc);
|
|
}
|
|
|
|
|
|
double
|
|
run_expr(struct expression *exp, int initial_call, struct expression **lastone)
|
|
{
|
|
/*
|
|
* We expect to find either
|
|
* a) A Open Paren
|
|
* or
|
|
* b) Val-> Op -> Val
|
|
* or
|
|
* c) Val-> Op -> Open Paren
|
|
*/
|
|
double val1, val2, res;
|
|
struct expression *op, *other_half, *rest;
|
|
|
|
if (exp->type == TYPE_PARN_OPEN) {
|
|
op = gather_exp_to_paren_close(exp->next, &val1);
|
|
} else if(exp->type == TYPE_VALUE_CON) {
|
|
val1 = exp->value;
|
|
op = exp->next;
|
|
} else if (exp->type == TYPE_VALUE_PMC) {
|
|
val1 = exp->value;
|
|
op = exp->next;
|
|
} else {
|
|
printf("Illegal value in %s huh?\n", __FUNCTION__);
|
|
exit(-1);
|
|
}
|
|
if (op == NULL) {
|
|
return (val1);
|
|
}
|
|
more_to_do:
|
|
other_half = op->next;
|
|
if (other_half->type == TYPE_PARN_OPEN) {
|
|
rest = gather_exp_to_paren_close(other_half->next, &val2);
|
|
} else if(other_half->type == TYPE_VALUE_CON) {
|
|
val2 = other_half->value;
|
|
rest = other_half->next;
|
|
} else if (other_half->type == TYPE_VALUE_PMC) {
|
|
val2 = other_half->value;
|
|
rest = other_half->next;
|
|
} else {
|
|
printf("Illegal2 value in %s huh?\n", __FUNCTION__);
|
|
exit(-1);
|
|
}
|
|
switch(op->type) {
|
|
case TYPE_OP_PLUS:
|
|
res = val1 + val2;
|
|
break;
|
|
case TYPE_OP_MINUS:
|
|
res = val1 - val2;
|
|
break;
|
|
case TYPE_OP_MULT:
|
|
res = val1 * val2;
|
|
break;
|
|
case TYPE_OP_DIVIDE:
|
|
if (val2 != 0.0)
|
|
res = val1 / val2;
|
|
else {
|
|
printf("Division by zero averted\n");
|
|
res = 1.0;
|
|
}
|
|
break;
|
|
default:
|
|
printf("Op is not an operator -- its %d\n",
|
|
op->type);
|
|
exit(-1);
|
|
break;
|
|
}
|
|
if (rest == NULL) {
|
|
if (lastone) {
|
|
*lastone = NULL;
|
|
}
|
|
return (res);
|
|
}
|
|
if ((rest->type == TYPE_PARN_CLOSE) && (initial_call == 0)) {
|
|
if (lastone) {
|
|
*lastone = rest->next;
|
|
}
|
|
return(res);
|
|
}
|
|
/* There is more, as in
|
|
* a + b + c
|
|
* where we just did a + b
|
|
* so now it becomes val1 is set to res and
|
|
* we need to proceed with the rest of it.
|
|
*/
|
|
val1 = res;
|
|
op = rest;
|
|
if ((op->type != TYPE_OP_PLUS) &&
|
|
(op->type != TYPE_OP_MULT) &&
|
|
(op->type != TYPE_OP_MINUS) &&
|
|
(op->type != TYPE_OP_DIVIDE)) {
|
|
printf("%s ending on type:%d not an op??\n", __FUNCTION__, op->type);
|
|
return(res);
|
|
}
|
|
if (op)
|
|
goto more_to_do;
|
|
return (res);
|
|
}
|
|
|
|
#ifdef STAND_ALONE_TESTING
|
|
|
|
static double
|
|
calc_expr(struct expression *exp)
|
|
{
|
|
struct expression *at;
|
|
double xx;
|
|
|
|
/* First clear PMC's setting */
|
|
for(at = exp; at != NULL; at = at->next) {
|
|
if (at->type == TYPE_VALUE_PMC) {
|
|
at->state = STATE_UNSET;
|
|
}
|
|
}
|
|
/* Now for all pmc's make up values .. here is where I would pull them */
|
|
for(at = exp; at != NULL; at = at->next) {
|
|
if (at->type == TYPE_VALUE_PMC) {
|
|
at->value = (random() * 1.0);
|
|
at->state = STATE_FILLED;
|
|
if (at->value == 0.0) {
|
|
/* So we don't have div by 0 */
|
|
at->value = 1.0;
|
|
}
|
|
}
|
|
}
|
|
/* Now lets calculate the expression */
|
|
print_exp(exp);
|
|
xx = run_expr(exp, 1, NULL);
|
|
printf("Answer is %f\n", xx);
|
|
return(xx);
|
|
}
|
|
|
|
|
|
int
|
|
main(int argc, char **argv)
|
|
{
|
|
struct expression *exp;
|
|
if (argc < 2) {
|
|
printf("Use %s expression\n", argv[0]);
|
|
return(-1);
|
|
}
|
|
exp = parse_expression(argv[1]);
|
|
printf("Now the calc\n");
|
|
calc_expr(exp);
|
|
return(0);
|
|
}
|
|
|
|
#endif
|