6ec01646dc
BMakefiles and other bits will follow. Requested by: Andrey Chernov Made world by: Chuck Robey
158 lines
4.8 KiB
C
158 lines
4.8 KiB
C
/* mpz_fac_ui(result, n) -- Set RESULT to N!.
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Copyright (C) 1991, 1993, 1994, 1995 Free Software Foundation, Inc.
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This file is part of the GNU MP Library.
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The GNU MP Library is free software; you can redistribute it and/or modify
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it under the terms of the GNU Library General Public License as published by
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the Free Software Foundation; either version 2 of the License, or (at your
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option) any later version.
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The GNU MP Library is distributed in the hope that it will be useful, but
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WITHOUT ANY WARRANTY; without even the implied warranty of MERCHANTABILITY
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or FITNESS FOR A PARTICULAR PURPOSE. See the GNU Library General Public
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License for more details.
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You should have received a copy of the GNU Library General Public License
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along with the GNU MP Library; see the file COPYING.LIB. If not, write to
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the Free Software Foundation, Inc., 59 Temple Place - Suite 330, Boston,
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MA 02111-1307, USA. */
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#ifdef DBG
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#include <stdio.h>
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#endif
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#include "gmp.h"
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#include "gmp-impl.h"
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#include "longlong.h"
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void
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#if __STDC__
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mpz_fac_ui (mpz_ptr result, unsigned long int n)
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#else
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mpz_fac_ui (result, n)
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mpz_ptr result;
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unsigned long int n;
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#endif
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{
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#if SIMPLE_FAC
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/* Be silly. Just multiply the numbers in ascending order. O(n**2). */
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unsigned long int k;
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mpz_set_ui (result, 1L);
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for (k = 2; k <= n; k++)
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mpz_mul_ui (result, result, k);
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#else
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/* Be smarter. Multiply groups of numbers in ascending order until the
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product doesn't fit in a limb. Multiply these partial product in a
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balanced binary tree fashion, to make the operand have as equal sizes
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as possible. When the operands have about the same size, mpn_mul
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becomes faster. */
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unsigned long int p, k;
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mp_limb_t p1, p0;
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/* Stack of partial products, used to make the computation balanced
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(i.e. make the sizes of the multiplication operands equal). The
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topmost position of MP_STACK will contain a one-limb partial product,
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the second topmost will contain a two-limb partial product, and so
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on. MP_STACK[0] will contain a partial product with 2**t limbs.
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To compute n! MP_STACK needs to be less than
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log(n)**2/log(BITS_PER_MP_LIMB), so 30 is surely enough. */
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#define MP_STACK_SIZE 30
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mpz_t mp_stack[MP_STACK_SIZE];
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/* TOP is an index into MP_STACK, giving the topmost element.
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TOP_LIMIT_SO_FAR is the largets value it has taken so far. */
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int top, top_limit_so_far;
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/* Count of the total number of limbs put on MP_STACK so far. This
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variable plays an essential role in making the compututation balanced.
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See below. */
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unsigned int tree_cnt;
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top = top_limit_so_far = -1;
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tree_cnt = 0;
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p = 1;
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for (k = 2; k <= n; k++)
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{
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/* Multiply the partial product in P with K. */
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umul_ppmm (p1, p0, (mp_limb_t) p, (mp_limb_t) k);
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/* Did we get overflow into the high limb, i.e. is the partial
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product now more than one limb? */
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if (p1 != 0)
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{
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tree_cnt++;
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if (tree_cnt % 2 == 0)
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{
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mp_size_t i;
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/* TREE_CNT is even (i.e. we have generated an even number of
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one-limb partial products), which means that we have a
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single-limb product on the top of MP_STACK. */
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mpz_mul_ui (mp_stack[top], mp_stack[top], p);
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/* If TREE_CNT is divisable by 4, 8,..., we have two
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similar-sized partial products with 2, 4,... limbs at
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the topmost two positions of MP_STACK. Multiply them
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to form a new partial product with 4, 8,... limbs. */
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for (i = 4; (tree_cnt & (i - 1)) == 0; i <<= 1)
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{
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mpz_mul (mp_stack[top - 1],
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mp_stack[top], mp_stack[top - 1]);
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top--;
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}
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}
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else
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{
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/* Put the single-limb partial product in P on the stack.
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(The next time we get a single-limb product, we will
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multiply the two together.) */
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top++;
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if (top > top_limit_so_far)
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{
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if (top > MP_STACK_SIZE)
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abort();
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/* The stack is now bigger than ever, initialize the top
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element. */
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mpz_init_set_ui (mp_stack[top], p);
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top_limit_so_far++;
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}
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else
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mpz_set_ui (mp_stack[top], p);
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}
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/* We ignored the last result from umul_ppmm. Put K in P as the
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first component of the next single-limb partial product. */
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p = k;
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}
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else
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/* We didn't get overflow in umul_ppmm. Put p0 in P and try
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with one more value of K. */
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p = p0; /* bogus if long != mp_limb_t */
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}
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/* We have partial products in mp_stack[0..top], in descending order.
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We also have a small partial product in p.
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Their product is the final result. */
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if (top < 0)
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mpz_set_ui (result, p);
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else
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mpz_mul_ui (result, mp_stack[top--], p);
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while (top >= 0)
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mpz_mul (result, result, mp_stack[top--]);
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/* Free the storage allocated for MP_STACK. */
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for (top = top_limit_so_far; top >= 0; top--)
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mpz_clear (mp_stack[top]);
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#endif
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}
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