bdc8631e01
remove the concept of a 'maintainer' of our make. there really isn't a need for any one committer to hold an exclusive lock or serve as a filter for this code.
32 lines
1.1 KiB
Makefile
32 lines
1.1 KiB
Makefile
# @(#)Makefile 5.2 (Berkeley) 12/28/90
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# $FreeBSD$
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PROG= make
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CFLAGS+= -I${.CURDIR}
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SRCS= arch.c buf.c compat.c cond.c dir.c for.c hash.c job.c main.c \
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make.c parse.c str.c suff.c targ.c var.c util.c
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SRCS+= lstAppend.c lstAtEnd.c lstAtFront.c lstClose.c lstConcat.c \
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lstDatum.c lstDeQueue.c lstDestroy.c lstDupl.c lstEnQueue.c \
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lstFind.c lstFindFrom.c lstFirst.c lstForEach.c lstForEachFrom.c \
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lstInit.c lstInsert.c lstIsAtEnd.c lstIsEmpty.c lstLast.c \
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lstMember.c lstNext.c lstOpen.c lstRemove.c lstReplace.c lstSucc.c
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.PATH: ${.CURDIR}/lst.lib
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# Set the shell which make(1) uses. Bourne is the default, but a decent
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# Korn shell works fine, and much faster. Using the C shell for this
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# will almost certainly break everything, but it's Unix tradition to
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# allow you to shoot yourself in the foot if you want to :-)
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MAKE_SHELL?= sh
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.if ${MAKE_SHELL} == "csh"
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CFLAGS+= -DDEFSHELL=0
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.elif ${MAKE_SHELL} == "sh"
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CFLAGS+= -DDEFSHELL=1
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.elif ${MAKE_SHELL} == "ksh"
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CFLAGS+= -DDEFSHELL=2
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.else
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.error "MAKE_SHELL must be set to one of \"csh\", \"sh\" or \"ksh\"."
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.endif
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.include <bsd.prog.mk>
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