freebsd-skq/contrib/telnet/libtelnet/kerberos.c
Jacques Vidrine 4b2eaea43f Background:
When libdes was replaced with OpenSSL's libcrypto, there were a few
 interfaces that the former implemented but the latter did not.  Because
 some software in the base system still depended upon these interfaces,
 we simply included them in our libcrypto (rnd_keys.c).

Now, finally get around to removing the dependencies on these
interfaces.  There were basically two cases:

  des_new_random_key -- This is just a wrapper for des_random_key, and
     these calls were replaced.

  des_init_random_number_generator et. al. -- A few functions were used
     by the application to seed libdes's PRNG.  These are not necessary
     when using libcrypto, as OpenSSL internally seeds the PRNG from
     /dev/random.  These calls were simply removed.

Again, some of the Kerberos 4 files have been taken off the vendor
branch.  I do not expect there to be future imports of KTH Kerberos 4.
2003-01-29 18:14:29 +00:00

507 lines
14 KiB
C

/*-
* Copyright (c) 1991, 1993
* The Regents of the University of California. All rights reserved.
*
* Redistribution and use in source and binary forms, with or without
* modification, are permitted provided that the following conditions
* are met:
* 1. Redistributions of source code must retain the above copyright
* notice, this list of conditions and the following disclaimer.
* 2. Redistributions in binary form must reproduce the above copyright
* notice, this list of conditions and the following disclaimer in the
* documentation and/or other materials provided with the distribution.
* 3. All advertising materials mentioning features or use of this software
* must display the following acknowledgement:
* This product includes software developed by the University of
* California, Berkeley and its contributors.
* 4. Neither the name of the University nor the names of its contributors
* may be used to endorse or promote products derived from this software
* without specific prior written permission.
*
* THIS SOFTWARE IS PROVIDED BY THE REGENTS AND CONTRIBUTORS ``AS IS'' AND
* ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
* IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
* ARE DISCLAIMED. IN NO EVENT SHALL THE REGENTS OR CONTRIBUTORS BE LIABLE
* FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
* DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
* OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
* HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
* LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
* OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
* SUCH DAMAGE.
*/
#include <sys/cdefs.h>
__FBSDID("$FreeBSD$");
#ifndef lint
static const char sccsid[] = "@(#)kerberos.c 8.3 (Berkeley) 5/30/95";
#endif /* not lint */
/*
* Copyright (C) 1990 by the Massachusetts Institute of Technology
*
* Export of this software from the United States of America is assumed
* to require a specific license from the United States Government.
* It is the responsibility of any person or organization contemplating
* export to obtain such a license before exporting.
*
* WITHIN THAT CONSTRAINT, permission to use, copy, modify, and
* distribute this software and its documentation for any purpose and
* without fee is hereby granted, provided that the above copyright
* notice appear in all copies and that both that copyright notice and
* this permission notice appear in supporting documentation, and that
* the name of M.I.T. not be used in advertising or publicity pertaining
* to distribution of the software without specific, written prior
* permission. M.I.T. makes no representations about the suitability of
* this software for any purpose. It is provided "as is" without express
* or implied warranty.
*/
#ifdef KRB4
#include <sys/types.h>
#include <arpa/telnet.h>
#include <openssl/des.h> /* BSD wont include this in krb.h, so we do it here */
#include <krb.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include "encrypt.h"
#include "auth.h"
#include "misc.h"
int kerberos4_cksum(unsigned char *, int);
int kuserok(AUTH_DAT *, char *);
extern int auth_debug_mode;
static unsigned char str_data[1024] = { IAC, SB, TELOPT_AUTHENTICATION, 0,
AUTHTYPE_KERBEROS_V4, };
#define KRB_AUTH 0 /* Authentication data follows */
#define KRB_REJECT 1 /* Rejected (reason might follow) */
#define KRB_ACCEPT 2 /* Accepted */
#define KRB_CHALLENGE 3 /* Challenge for mutual auth. */
#define KRB_RESPONSE 4 /* Response for mutual auth. */
static KTEXT_ST auth;
static char name[ANAME_SZ];
static AUTH_DAT adat = { 0, "", "", "", 0, {}, 0, 0, 0, { 0, "", 0 } };
#ifdef ENCRYPTION
static Block session_key = { 0 };
static des_key_schedule sched;
static Block challenge = { 0 };
#endif /* ENCRYPTION */
static char krb_service_name[] = "rcmd";
static char empty[] = "";
static int
Data(Authenticator *ap, int type, const unsigned char *d, int c)
{
unsigned char *p = str_data + 4;
const unsigned char *cd = d;
if (c == -1)
c = strlen(cd);
if (auth_debug_mode) {
printf("%s:%d: [%d] (%d)",
str_data[3] == TELQUAL_IS ? ">>>IS" : ">>>REPLY",
str_data[3],
type, c);
printd(d, c);
printf("\r\n");
}
*p++ = ap->type;
*p++ = ap->way;
*p++ = type;
while (c-- > 0) {
if ((*p++ = *cd++) == IAC)
*p++ = IAC;
}
*p++ = IAC;
*p++ = SE;
if (str_data[3] == TELQUAL_IS)
printsub('>', &str_data[2], p - (&str_data[2]));
return(net_write(str_data, p - str_data));
}
int
kerberos4_init(Authenticator *ap __unused, int server)
{
FILE *fp;
if (server) {
str_data[3] = TELQUAL_REPLY;
if ((fp = fopen(KEYFILE, "r")) == NULL)
return(0);
fclose(fp);
} else {
str_data[3] = TELQUAL_IS;
}
return(1);
}
char dst_realm_buf[REALM_SZ], *dest_realm = NULL;
int dst_realm_sz = REALM_SZ;
int
kerberos4_send(Authenticator *ap)
{
KTEXT_ST lauth;
char instance[INST_SZ];
char *realm;
CREDENTIALS cred;
int r;
printf("[ Trying KERBEROS4 ... ]\n");
if (!UserNameRequested) {
if (auth_debug_mode) {
printf("Kerberos V4: no user name supplied\r\n");
}
return(0);
}
memset(instance, 0, sizeof(instance));
if ((realm = krb_get_phost(RemoteHostName)))
strncpy(instance, realm, sizeof(instance));
instance[sizeof(instance)-1] = '\0';
realm = dest_realm ? dest_realm : krb_realmofhost(RemoteHostName);
if (!realm) {
printf("Kerberos V4: no realm for %s\r\n", RemoteHostName);
return(0);
}
if ((r = krb_mk_req(&lauth, krb_service_name, instance, realm, 0L))) {
printf("mk_req failed: %s\r\n", krb_err_txt[r]);
return(0);
}
if ((r = krb_get_cred(krb_service_name, instance, realm, &cred))) {
printf("get_cred failed: %s\r\n", krb_err_txt[r]);
return(0);
}
if (!auth_sendname(UserNameRequested, strlen(UserNameRequested))) {
if (auth_debug_mode)
printf("Not enough room for user name\r\n");
return(0);
}
if (auth_debug_mode)
printf("Sent %d bytes of authentication data\r\n", lauth.length);
if (!Data(ap, KRB_AUTH, (void *)lauth.dat, lauth.length)) {
if (auth_debug_mode)
printf("Not enough room for authentication data\r\n");
return(0);
}
#ifdef ENCRYPTION
/*
* If we are doing mutual authentication, get set up to send
* the challenge, and verify it when the response comes back.
*/
if ((ap->way & AUTH_HOW_MASK) == AUTH_HOW_MUTUAL) {
register int i;
des_key_sched(&cred.session, sched);
des_random_key(&session_key);
des_ecb_encrypt(&session_key, &session_key, sched, 0);
des_ecb_encrypt(&session_key, &challenge, sched, 0);
/*
* Increment the challenge by 1, and encrypt it for
* later comparison.
*/
for (i = 7; i >= 0; --i) {
register int x;
x = (unsigned int)challenge[i] + 1;
challenge[i] = x; /* ignore overflow */
if (x < 256) /* if no overflow, all done */
break;
}
des_ecb_encrypt(&challenge, &challenge, sched, 1);
}
#endif /* ENCRYPTION */
if (auth_debug_mode) {
printf("CK: %d:", kerberos4_cksum(lauth.dat, lauth.length));
printd(lauth.dat, lauth.length);
printf("\r\n");
printf("Sent Kerberos V4 credentials to server\r\n");
}
return(1);
}
void
kerberos4_is(Authenticator *ap, unsigned char *data, int cnt)
{
#ifdef ENCRYPTION
Session_Key skey;
Block datablock;
#endif /* ENCRYPTION */
char realm[REALM_SZ];
char instance[INST_SZ];
int r;
if (cnt-- < 1)
return;
switch (*data++) {
case KRB_AUTH:
if (krb_get_lrealm(realm, 1) != KSUCCESS) {
Data(ap, KRB_REJECT, "No local V4 Realm.", -1);
auth_finished(ap, AUTH_REJECT);
if (auth_debug_mode)
printf("No local realm\r\n");
return;
}
memmove((void *)auth.dat, (void *)data, auth.length = cnt);
if (auth_debug_mode) {
printf("Got %d bytes of authentication data\r\n", cnt);
printf("CK: %d:", kerberos4_cksum(auth.dat, auth.length));
printd(auth.dat, auth.length);
printf("\r\n");
}
instance[0] = '*'; instance[1] = 0;
if ((r = krb_rd_req(&auth, krb_service_name,
instance, 0, &adat, empty))) {
if (auth_debug_mode)
printf("Kerberos failed him as %s\r\n", name);
Data(ap, KRB_REJECT, krb_err_txt[r], -1);
auth_finished(ap, AUTH_REJECT);
return;
}
#ifdef ENCRYPTION
memmove((void *)session_key, (void *)adat.session, sizeof(Block));
#endif /* ENCRYPTION */
krb_kntoln(&adat, name);
if (UserNameRequested && !kuserok(&adat, UserNameRequested))
Data(ap, KRB_ACCEPT, NULL, 0);
else
Data(ap, KRB_REJECT, "user is not authorized", -1);
auth_finished(ap, AUTH_USER);
break;
case KRB_CHALLENGE:
#ifndef ENCRYPTION
Data(ap, KRB_RESPONSE, NULL, 0);
#else /* ENCRYPTION */
if (!VALIDKEY(session_key)) {
/*
* We don't have a valid session key, so just
* send back a response with an empty session
* key.
*/
Data(ap, KRB_RESPONSE, NULL, 0);
break;
}
des_key_sched(&session_key, sched);
memmove((void *)datablock, (void *)data, sizeof(Block));
/*
* Take the received encrypted challenge, and encrypt
* it again to get a unique session_key for the
* ENCRYPT option.
*/
des_ecb_encrypt(&datablock, &session_key, sched, 1);
skey.type = SK_DES;
skey.length = 8;
skey.data = session_key;
encrypt_session_key(&skey, 1);
/*
* Now decrypt the received encrypted challenge,
* increment by one, re-encrypt it and send it back.
*/
des_ecb_encrypt(&datablock, &challenge, sched, 0);
for (r = 7; r >= 0; r--) {
register int t;
t = (unsigned int)challenge[r] + 1;
challenge[r] = t; /* ignore overflow */
if (t < 256) /* if no overflow, all done */
break;
}
des_ecb_encrypt(&challenge, &challenge, sched, 1);
Data(ap, KRB_RESPONSE, challenge, sizeof(challenge));
#endif /* ENCRYPTION */
break;
default:
if (auth_debug_mode)
printf("Unknown Kerberos option %d\r\n", data[-1]);
Data(ap, KRB_REJECT, NULL, 0);
break;
}
}
void
kerberos4_reply(Authenticator *ap, unsigned char *data, int cnt)
{
#ifdef ENCRYPTION
Session_Key skey;
#endif /* ENCRYPTION */
if (cnt-- < 1)
return;
switch (*data++) {
case KRB_REJECT:
if (cnt > 0) {
printf("[ Kerberos V4 refuses authentication because %.*s ]\r\n",
cnt, data);
} else
printf("[ Kerberos V4 refuses authentication ]\r\n");
auth_send_retry();
return;
case KRB_ACCEPT:
printf("[ Kerberos V4 accepts you ]\n");
if ((ap->way & AUTH_HOW_MASK) == AUTH_HOW_MUTUAL) {
/*
* Send over the encrypted challenge.
*/
#ifndef ENCRYPTION
Data(ap, KRB_CHALLENGE, NULL, 0);
#else /* ENCRYPTION */
Data(ap, KRB_CHALLENGE, session_key,
sizeof(session_key));
des_ecb_encrypt(&session_key, &session_key, sched, 1);
skey.type = SK_DES;
skey.length = 8;
skey.data = session_key;
encrypt_session_key(&skey, 0);
#endif /* ENCRYPTION */
return;
}
auth_finished(ap, AUTH_USER);
return;
case KRB_RESPONSE:
#ifdef ENCRYPTION
/*
* Verify that the response to the challenge is correct.
*/
if ((cnt != sizeof(Block)) ||
(0 != memcmp((void *)data, (void *)challenge,
sizeof(challenge))))
{
#endif /* ENCRYPTION */
printf("[ Kerberos V4 challenge failed!!! ]\r\n");
auth_send_retry();
return;
#ifdef ENCRYPTION
}
printf("[ Kerberos V4 challenge successful ]\r\n");
auth_finished(ap, AUTH_USER);
#endif /* ENCRYPTION */
break;
default:
if (auth_debug_mode)
printf("Unknown Kerberos option %d\r\n", data[-1]);
return;
}
}
int
kerberos4_status(Authenticator *ap __unused, char *nam, int level)
{
if (level < AUTH_USER)
return(level);
if (UserNameRequested && !kuserok(&adat, UserNameRequested)) {
strcpy(nam, UserNameRequested);
return(AUTH_VALID);
} else
return(AUTH_USER);
}
#define BUMP(buf, len) while (*(buf)) {++(buf), --(len);}
#define ADDC(buf, len, c) if ((len) > 0) {*(buf)++ = (c); --(len);}
void
kerberos4_printsub(unsigned char *data, int cnt, unsigned char *buf, int buflen)
{
char lbuf[32];
register int i;
buf[buflen-1] = '\0'; /* make sure its NULL terminated */
buflen -= 1;
switch(data[3]) {
case KRB_REJECT: /* Rejected (reason might follow) */
strncpy((char *)buf, " REJECT ", buflen);
goto common;
case KRB_ACCEPT: /* Accepted (name might follow) */
strncpy((char *)buf, " ACCEPT ", buflen);
common:
BUMP(buf, buflen);
if (cnt <= 4)
break;
ADDC(buf, buflen, '"');
for (i = 4; i < cnt; i++)
ADDC(buf, buflen, data[i]);
ADDC(buf, buflen, '"');
ADDC(buf, buflen, '\0');
break;
case KRB_AUTH: /* Authentication data follows */
strncpy((char *)buf, " AUTH", buflen);
goto common2;
case KRB_CHALLENGE:
strncpy((char *)buf, " CHALLENGE", buflen);
goto common2;
case KRB_RESPONSE:
strncpy((char *)buf, " RESPONSE", buflen);
goto common2;
default:
sprintf(lbuf, " %d (unknown)", data[3]);
strncpy((char *)buf, lbuf, buflen);
common2:
BUMP(buf, buflen);
for (i = 4; i < cnt; i++) {
sprintf(lbuf, " %d", data[i]);
strncpy((char *)buf, lbuf, buflen);
BUMP(buf, buflen);
}
break;
}
}
int
kerberos4_cksum(unsigned char *d, int n)
{
int ck = 0;
/*
* A comment is probably needed here for those not
* well versed in the "C" language. Yes, this is
* supposed to be a "switch" with the body of the
* "switch" being a "while" statement. The whole
* purpose of the switch is to allow us to jump into
* the middle of the while() loop, and then not have
* to do any more switch()s.
*
* Some compilers will spit out a warning message
* about the loop not being entered at the top.
*/
switch (n&03)
while (n > 0) {
case 0:
ck ^= (int)*d++ << 24;
--n;
case 3:
ck ^= (int)*d++ << 16;
--n;
case 2:
ck ^= (int)*d++ << 8;
--n;
case 1:
ck ^= (int)*d++;
--n;
}
return(ck);
}
#endif