This one is strange and goes against my rusty compiler knowledge.
The global declaration
struct sockaddr whereto;
produces for both i386 && alpha:
.comm whereto,16,1
which means common storage, byte aligned. Ahem. I though structs
were supposed to be ALDOUBLE always? I mean, w/o pragma packed?
Later on, this address is coerced to:
to = (struct sockaddr_in *)&whereto;
Up until now, we've been fine on alpha because the address
just ended up aligned to a 4 byte boundary. Lately, though,
it end up as:
0000000120027b0f B whereto
And, tra la, you get unaligned access faults. The solution I picked, in
lieu of understanding what the compiler was doing, is to put whereto
as a union of a sockaddr and sockaddr_in. That's more formally correct
if somewhat awkward looking.
de06014a31