net/qede: get consumer index once
Calling ecore_chain_get_cons_idx repeatedly is slower than calling it once and using the result for the remainder of qede_process_tx_compl. Signed-off-by: Balazs Nemeth <bnemeth@redhat.com> Reviewed-by: Igor Russkikh <irusskikh@marvell.com>
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@ -882,12 +882,13 @@ qede_tx_queue_start(struct rte_eth_dev *eth_dev, uint16_t tx_queue_id)
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return rc;
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}
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static inline void
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static inline uint16_t
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qede_free_tx_pkt(struct qede_tx_queue *txq)
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{
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struct rte_mbuf *mbuf;
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uint16_t nb_segs;
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uint16_t idx;
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uint16_t ret;
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idx = TX_CONS(txq);
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mbuf = txq->sw_tx_ring[idx];
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@ -895,20 +896,22 @@ qede_free_tx_pkt(struct qede_tx_queue *txq)
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nb_segs = mbuf->nb_segs;
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PMD_TX_LOG(DEBUG, txq, "nb_segs to free %u\n", nb_segs);
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ret = nb_segs;
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while (nb_segs) {
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/* It's like consuming rxbuf in recv() */
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ecore_chain_consume(&txq->tx_pbl);
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txq->nb_tx_avail++;
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nb_segs--;
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}
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rte_pktmbuf_free(mbuf);
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txq->sw_tx_ring[idx] = NULL;
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txq->sw_tx_cons++;
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PMD_TX_LOG(DEBUG, txq, "Freed tx packet\n");
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} else {
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ecore_chain_consume(&txq->tx_pbl);
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txq->nb_tx_avail++;
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ret = 1;
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}
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return ret;
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}
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static inline void
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@ -916,19 +919,22 @@ qede_process_tx_compl(__rte_unused struct ecore_dev *edev,
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struct qede_tx_queue *txq)
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{
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uint16_t hw_bd_cons;
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#ifdef RTE_LIBRTE_QEDE_DEBUG_TX
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uint16_t sw_tx_cons;
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#endif
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uint16_t remaining;
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rte_compiler_barrier();
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sw_tx_cons = ecore_chain_get_cons_idx(&txq->tx_pbl);
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hw_bd_cons = rte_le_to_cpu_16(*txq->hw_cons_ptr);
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#ifdef RTE_LIBRTE_QEDE_DEBUG_TX
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sw_tx_cons = ecore_chain_get_cons_idx(&txq->tx_pbl);
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PMD_TX_LOG(DEBUG, txq, "Tx Completions = %u\n",
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abs(hw_bd_cons - sw_tx_cons));
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#endif
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while (hw_bd_cons != ecore_chain_get_cons_idx(&txq->tx_pbl))
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qede_free_tx_pkt(txq);
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remaining = hw_bd_cons - sw_tx_cons;
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txq->nb_tx_avail += remaining;
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while (remaining)
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remaining -= qede_free_tx_pkt(txq);
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}
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static int qede_drain_txq(struct qede_dev *qdev,
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