ip_frag: fix double free of chained mbufs

If any fragment hole is found in ipv4_frag_reassemble() and
ipv6_frag_reassemble(), whole ip_frag_pkt mbufs are moved to death-row.
Any mbufs already chained to another mbuf are freed multiple times as
there are still in ip_frag_pkt array.

Signed-off-by: Chaeyong Chong <cychong@gmail.com>
Acked-by: Konstantin Ananyev <konstantin.ananyev@intel.com>
This commit is contained in:
Chaeyong Chong 2016-04-22 02:28:01 +09:00 committed by Thomas Monjalon
parent 31ca33ff93
commit 62aaf5524c
3 changed files with 16 additions and 4 deletions

View File

@ -76,8 +76,8 @@ struct ip_frag_pkt * ip_frag_lookup(struct rte_ip_frag_tbl *tbl,
struct ip_frag_pkt **free, struct ip_frag_pkt **stale);
/* these functions need to be declared here as ip_frag_process relies on them */
struct rte_mbuf * ipv4_frag_reassemble(const struct ip_frag_pkt *fp);
struct rte_mbuf * ipv6_frag_reassemble(const struct ip_frag_pkt *fp);
struct rte_mbuf *ipv4_frag_reassemble(struct ip_frag_pkt *fp);
struct rte_mbuf *ipv6_frag_reassemble(struct ip_frag_pkt *fp);

View File

@ -41,11 +41,12 @@
* Reassemble fragments into one packet.
*/
struct rte_mbuf *
ipv4_frag_reassemble(const struct ip_frag_pkt *fp)
ipv4_frag_reassemble(struct ip_frag_pkt *fp)
{
struct ipv4_hdr *ip_hdr;
struct rte_mbuf *m, *prev;
uint32_t i, n, ofs, first_len;
uint32_t curr_idx = 0;
first_len = fp->frags[IP_FIRST_FRAG_IDX].len;
n = fp->last_idx - 1;
@ -53,6 +54,7 @@ ipv4_frag_reassemble(const struct ip_frag_pkt *fp)
/*start from the last fragment. */
m = fp->frags[IP_LAST_FRAG_IDX].mb;
ofs = fp->frags[IP_LAST_FRAG_IDX].ofs;
curr_idx = IP_LAST_FRAG_IDX;
while (ofs != first_len) {
@ -67,6 +69,10 @@ ipv4_frag_reassemble(const struct ip_frag_pkt *fp)
rte_pktmbuf_adj(m, (uint16_t)(m->l2_len + m->l3_len));
rte_pktmbuf_chain(fp->frags[i].mb, m);
/* this mbuf should not be accessed directly */
fp->frags[curr_idx].mb = NULL;
curr_idx = i;
/* update our last fragment and offset. */
m = fp->frags[i].mb;
ofs = fp->frags[i].ofs;

View File

@ -59,13 +59,14 @@ ip_frag_memmove(char *dst, char *src, int len)
* Reassemble fragments into one packet.
*/
struct rte_mbuf *
ipv6_frag_reassemble(const struct ip_frag_pkt *fp)
ipv6_frag_reassemble(struct ip_frag_pkt *fp)
{
struct ipv6_hdr *ip_hdr;
struct ipv6_extension_fragment *frag_hdr;
struct rte_mbuf *m, *prev;
uint32_t i, n, ofs, first_len;
uint32_t last_len, move_len, payload_len;
uint32_t curr_idx = 0;
first_len = fp->frags[IP_FIRST_FRAG_IDX].len;
n = fp->last_idx - 1;
@ -74,6 +75,7 @@ ipv6_frag_reassemble(const struct ip_frag_pkt *fp)
m = fp->frags[IP_LAST_FRAG_IDX].mb;
ofs = fp->frags[IP_LAST_FRAG_IDX].ofs;
last_len = fp->frags[IP_LAST_FRAG_IDX].len;
curr_idx = IP_LAST_FRAG_IDX;
payload_len = ofs + last_len;
@ -90,6 +92,10 @@ ipv6_frag_reassemble(const struct ip_frag_pkt *fp)
rte_pktmbuf_adj(m, (uint16_t)(m->l2_len + m->l3_len));
rte_pktmbuf_chain(fp->frags[i].mb, m);
/* this mbuf should not be accessed directly */
fp->frags[curr_idx].mb = NULL;
curr_idx = i;
/* update our last fragment and offset. */
m = fp->frags[i].mb;
ofs = fp->frags[i].ofs;