memzone: document reserving zero-length memzones

Currently, reserving a memzone with length set to 0 will not trigger
any memory allocations, and memzone will instead be looking through
already allocated memory only. Document this limitation.

Signed-off-by: Anatoly Burakov <anatoly.burakov@intel.com>
This commit is contained in:
Anatoly Burakov 2018-05-03 17:25:58 +01:00 committed by Thomas Monjalon
parent a82377cab8
commit 7785c5588d

View File

@ -77,6 +77,10 @@ struct rte_memzone {
* correctly filled memzone descriptor. If the allocation cannot be
* done, return NULL.
*
* @note Reserving memzones with len set to 0 will only attempt to allocate
* memzones from memory that is already available. It will not trigger any
* new allocations.
*
* @param name
* The name of the memzone. If it already exists, the function will
* fail and return NULL.
@ -130,6 +134,10 @@ const struct rte_memzone *rte_memzone_reserve(const char *name,
* descriptor. If the allocation cannot be done or if the alignment
* is not a power of 2, returns NULL.
*
* @note Reserving memzones with len set to 0 will only attempt to allocate
* memzones from memory that is already available. It will not trigger any
* new allocations.
*
* @param name
* The name of the memzone. If it already exists, the function will
* fail and return NULL.
@ -188,6 +196,10 @@ const struct rte_memzone *rte_memzone_reserve_aligned(const char *name,
* boundary. That implies that requested length should be less or equal
* then boundary.
*
* @note Reserving memzones with len set to 0 will only attempt to allocate
* memzones from memory that is already available. It will not trigger any
* new allocations.
*
* @param name
* The name of the memzone. If it already exists, the function will
* fail and return NULL.