mempool: remove check for bad IOVA when populating
Currently, mempool will check if IOVA is bad for a segment, and reject
the IOVA if hugepages are also enabled. This check is wrong because now
that we have external memory segments, they are allowed to have their
IOVA's to be invalid. This check also doesn't make much sense in the
first place, because the following code can handle bad IOVA's perfectly
well (and in fact, this check is not triggering a failure when
--no-huge option is enabled), so there is not much sense to check for
this in the first place.
Fixes: 950e8fb4e1
("mem: allow registering external memory areas")
Cc: stable@dpdk.org
Signed-off-by: Anatoly Burakov <anatoly.burakov@intel.com>
Acked-by: Olivier Matz <olivier.matz@6wind.com>
Tested-by: Bo Chen <box.c.chen@intel.com>
This commit is contained in:
parent
2a7fd3ef38
commit
84191ddeb5
@ -390,11 +390,6 @@ rte_mempool_populate_virt(struct rte_mempool *mp, char *addr,
|
||||
|
||||
iova = get_iova(addr + off);
|
||||
|
||||
if (iova == RTE_BAD_IOVA && rte_eal_has_hugepages()) {
|
||||
ret = -EINVAL;
|
||||
goto fail;
|
||||
}
|
||||
|
||||
/* populate with the largest group of contiguous pages */
|
||||
for (phys_len = RTE_MIN(
|
||||
(size_t)(RTE_PTR_ALIGN_CEIL(addr + off + 1, pg_sz) -
|
||||
|
Loading…
Reference in New Issue
Block a user