common/mlx5: wrap memory allocation on Windows

This commit is the Windows equivalent of the Linux implementation.  The
APIs included in this commit: mlx5_os_malloc(), mlx5_os_free(). For
memory allocations (with or without alignment) we always call
_aligned_malloc(). Even if zero alignment was requested in the first
place - we always select a minimal alignment value. In this way when the
memory is free - it is always safe to call _aligned_free().

Signed-off-by: Ophir Munk <ophirmu@nvidia.com>
Acked-by: Matan Azrad <matan@nvidia.com>

drivers/common/mlx5/windows/mlx5_common_os.h

@@ -0,0 +1,51 @@
+/* SPDX-License-Identifier: BSD-3-Clause
+ * Copyright 2020 Mellanox Technologies, Ltd
+ */
+
+#ifndef RTE_PMD_MLX5_COMMON_OS_H_
+#define RTE_PMD_MLX5_COMMON_OS_H_
+
+#include <stdio.h>
+
+#include "mlx5_autoconf.h"
+#include "mlx5_glue.h"
+#include "mlx5_malloc.h"
+
+/**
+ * This API allocates aligned or non-aligned memory.  The free can be on either
+ * aligned or nonaligned memory.  To be protected - even though there may be no
+ * alignment - in Windows this API will unconditioanlly call _aligned_malloc()
+ * with at least a minimal alignment size.
+ *
+ * @param[in] align
+ *    The alignment value, which must be an integer power of 2 (or 0 for
+ *    non-alignment)
+ * @param[in] size
+ *    Size in bytes to allocate
+ *
+ * @return
+ *    Valid pointer to allocated memory, NULL in case of failure
+ */
+static inline void *
+mlx5_os_malloc(size_t align, size_t size)
+{
+	if (align < MLX5_MALLOC_ALIGNMENT)
+		align = MLX5_MALLOC_ALIGNMENT;
+	return _aligned_malloc(size, align);
+}
+
+/**
+ * This API de-allocates a memory that originally could have been allocated
+ * aligned or non-aligned. In Windows since the allocation was with
+ * _aligned_malloc() - it is safe to always call _aligned_free().
+ *
+ * @param[in] addr
+ *    Pointer to address to free
+ *
+ */
+static inline void
+mlx5_os_free(void *addr)
+{
+	_aligned_free(addr);
+}
+#endif /* RTE_PMD_MLX5_COMMON_OS_H_ */