mbuf: avoid implicit demotion in 64-bit arithmetic
GCC 8.1 warned: In function 'rte_validate_tx_offload': rte_mbuf.h:2112:19: warning: conversion to 'uint64_t' {aka 'long unsigned int'} from 'int' may change the sign of the result [-Wsign-conversion] inner_l3_offset += m->outer_l2_len + m->outer_l3_len; ^~ uint64_t inner_l3_offset... /* fields for TX offloading of tunnels */ uint64_t outer_l3_len:9; /**< Outer L3 (IP) Hdr Length. */ uint64_t outer_l2_len:7; /**< Outer L2 (MAC) Hdr Length. */ We want to do the arithmetic entirely in uint64_t space, but with the +=, the rhs type becomes int since the bitfields will fit in int. Elaborate the artithmetic to be u64 = u64 + int + int, so the type of the result is correct to be stored in the u64. Fixes: 4fb7e803eb ("ethdev: add Tx preparation") Cc: stable@dpdk.org Signed-off-by: Andy Green <andy@warmcat.com> Acked-by: Bruce Richardson <bruce.richardson@intel.com>
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@ -2112,7 +2112,11 @@ rte_validate_tx_offload(const struct rte_mbuf *m)
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return 0;
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if (ol_flags & PKT_TX_OUTER_IP_CKSUM)
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inner_l3_offset += m->outer_l2_len + m->outer_l3_len;
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/* NB: elaborating the addition like this instead of using
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* += gives the result uint64_t type instead of int,
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* avoiding compiler warnings on gcc 8.1 at least */
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inner_l3_offset = inner_l3_offset + m->outer_l2_len +
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m->outer_l3_len;
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/* Headers are fragmented */
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if (rte_pktmbuf_data_len(m) < inner_l3_offset + m->l3_len + m->l4_len)
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