mbuf: avoid implicit demotion in 64-bit arithmetic

GCC 8.1 warned:

In function 'rte_validate_tx_offload':
rte_mbuf.h:2112:19: warning: conversion to 'uint64_t'
{aka 'long unsigned int'} from 'int' may change the
sign of the result [-Wsign-conversion]
  inner_l3_offset += m->outer_l2_len + m->outer_l3_len;
                   ^~

  uint64_t inner_l3_offset...

  /* fields for TX offloading of tunnels */
  uint64_t outer_l3_len:9; /**< Outer L3 (IP) Hdr Length. */
  uint64_t outer_l2_len:7; /**< Outer L2 (MAC) Hdr Length. */

We want to do the arithmetic entirely in uint64_t
space, but with the +=, the rhs type becomes int since the
bitfields will fit in int.

Elaborate the artithmetic to be u64 = u64 + int + int, so
the type of the result is correct to be stored in the u64.

Fixes: 4fb7e803eb ("ethdev: add Tx preparation")
Cc: stable@dpdk.org

Signed-off-by: Andy Green <andy@warmcat.com>
Acked-by: Bruce Richardson <bruce.richardson@intel.com>
This commit is contained in:
Andy Green 2018-05-22 09:24:32 +08:00 committed by Thomas Monjalon
parent 50f239c908
commit ef5092e16b

View File

@ -2112,7 +2112,11 @@ rte_validate_tx_offload(const struct rte_mbuf *m)
return 0;
if (ol_flags & PKT_TX_OUTER_IP_CKSUM)
inner_l3_offset += m->outer_l2_len + m->outer_l3_len;
/* NB: elaborating the addition like this instead of using
* += gives the result uint64_t type instead of int,
* avoiding compiler warnings on gcc 8.1 at least */
inner_l3_offset = inner_l3_offset + m->outer_l2_len +
m->outer_l3_len;
/* Headers are fragmented */
if (rte_pktmbuf_data_len(m) < inner_l3_offset + m->l3_len + m->l4_len)